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krek1111 [17]
4 years ago
9

Several steps are involved in the industrial production of sulfuric acid. One step involves the oxidation of sulfur dioxide gas

to form sulfur trioxide gas. A catalyst is used to increase the rate of production of sulfur trioxide gas. In a rigid cylinder with a movable piston, this reaction reaches equilibrium, as represented by the equation below.
2SO2(g) + O2(g) <==> 2SO3(g) + 392 kJ
Explain, in terms of collision theory, why increasing the pressure of the gases in the cylinder increases the rate of the forward reaction.
Determine the amount of heat released by the production of 1.0 mole of SO3(g).
State, in terms of the concentration of SO3(g) , what occurs when more O2(g) is added to the reaction at equilibrium.
Chemistry
1 answer:
sertanlavr [38]4 years ago
6 0
Increasing the pressure of the gas increases the intermolecuar forces of attraction between the molecules because the distance between the molecules are being reduced by the action of the piston. 
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A 4.08 g sample of a compound composed of nitrogen and oxygen contains 3.02 g of oxygen. What is the empirical formula
blsea [12.9K]

Answer:

Explanation:

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2 years ago
What is the symbol of an ion with 16 protons, 18 neutrons, and 18 electrons? what is the symbol for an ion that has 16 pro-tons,
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When we go to periodic table, Sulfur is an element that has 16 protons and 16 electrons.

when there is 18 electrons, with number of two electrons more than protons. This makes it an ion and the ion has a -2 charge.

So when there is16 protons, 18 neutrons, and 18 electrons the symbol is S⁻².

The neutrons have no charge but they add only mass to the elements. So when there is 16 neutrons, it doesn't change the symbol of ion.

3 0
3 years ago
Which part(s) of the reaction 2 HD(g) ⇀↽ H2(g) + D2(g) will be favored by an increase in the total pressure (resulting in compre
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Answer:

Neither side is favored

Explanation:

In a reaction at equilibrium in which reactants and products are gases, pressure is a factor that produces a shift of the equilibrium position. When the pressure is increased, the equilibrium is shifted to the side of the reaction with a fewer moles. In this reaction:

2 HD(g) ⇀↽ H₂(g) + D₂(g)

There is the same number of moles on both sides:

reactants side: 2 moles HD

products side: 1 mol H₂ + 1 mol D₂ = 2 moles

Therefore, the equilibrium position will not change.

7 0
3 years ago
Estimate the percent ionic character of the co bond. (note that the electronegativity of c is 2.5 and that of o is 3.5.)
deff fn [24]

From the calcuation, the percent ionic character of the bond is  70%

<h3>What is percent ionic character?</h3>

The term percent ionic character has to do with the degree of ionic bonding that is contained in a compound. It can be estimated from the electronegativity of each element.

We can use the formula; 100(1 - e^(-ΔEN² / 4))

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100(1 - e^(-1)^2/4)

= 70%

Learn more about percent ionic character:brainly.com/question/7034446

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2 years ago
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Paper chromatography is a useful technique for ink analysis. Ink consists of several dyes, which can be separated individually. When the ink is exposed to certain solvent mixtures the dyes of the ink dissolves in the mixture. Each ink components acquire distinct distance according to the retention factor. Some inks are water soluble, so the solvent used for separation should be water. Inks which are not water soluble are soluble in other solvents like alcohol.

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3 years ago
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