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frosja888 [35]
4 years ago
5

If 5.0 g of copper cools from 35.0oC to 22.6 oC and loses 23.6 J of heat, what is the specific heat of copper? a. 0.038 J/(g. oC

) b. 0.62 J/(g. oC) c. 0.076 J/(g. oC) d. 0.38 J/(g. oC)
Chemistry
1 answer:
Annette [7]4 years ago
5 0

Answer:

c = 0.38 J/(g-°C)

Explanation:

Given that,

Mass of copper, m = 5 g

Initial temperature, T_i=35^{\circ} C

Final temperature, T_f=22.6^{\circ} C

When copper cools, it looses 23.6 J of heat. We need to find the specific heat of copper. The heat lost is given by :

Q=mc\Delta T

c is specific heat

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{23.6}{5\times (22.6-35)}\\\\c=0.38\ J/g-^{\circ} C

Hence, the correct option is d.

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