Answer:E
Explanation:
The electron is expected to be in any of the 4p orbitals. For the 4p orbitals
n=4
l=1
ml=-1,0,1
ms=-1/2 or +1/2
All the ml and ms configurations are equiprobable hence the answer.
Answer:
The answer to your question is below
Explanation:
a) CI Chlorine is located in group VIIA, so its must gain one electron to be stable.
b) Se Selenium is located in group VIA, it must gain 2 electrons to be stable.
c) N Nitrogen is located in group VA, it must gain 3 electrons to be stable.
d) I Iodine is located in group VIIA, so it must gain 1 electron to be stable.
e) S sulfur is located in group VIA, so it must gain 2 electrons to be stable.
Answer is: mass fo ammonium chloride is 93.625 grams.
V(NH₄Cl) = 5 L.
c(NH₄Cl) = 0.35 M.
n(NH₄Cl) = V(NH₄Cl) · c(NH₄Cl).
n(NH₄Cl) = 5 L · 0.35 mol/L.
n(NH₄Cl) = 1.75 mol.
M(NH₄Cl) = 14 + 1·4 + 35.5 · g/mol = 53.5 g/mol.
m(NH₄Cl) = n(NH₄Cl) · M(NH₄Cl).
m(NH₄Cl) = 1.75 mol · 53.5 g/mol.
m(NH₄Cl) = 93.625 g.
Multiply the mass by the abundance and add each. Make sure to convert the percentage into a decimal. (49.946 * .043) + (51.941 * .838) + (52.941 * .095) + (53.939 * .024) = 51.99 round up using sig figs and the answer is c. 52.00 amu
Answer:
The area around the nucleus must be of low mass.
Explanation:
Rutherford`s experiment showed that there are some positive charges in the center of the atoms, and because they are all together, they will give a great mass to the atom.
It was quite different from Thomson`s experiment, in which it was thought that the negative charges were mixed with the positive charges, around the atom (like a Pudding Model). In Rutherford`s experiment, because the direction of beta particles, it was the prediction of the positive nucleus.
Hope this info is useful.
