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4 years ago

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Physics

1 answer:

g100num [7]4 years ago

3 0

Answer:

Average acceleration is the change in velocity divided by an elapsed time. For instance, if the velocity of a marble increases from 0 to 60 cm/s in 3 seconds, its average acceleration would be 20 cm/s/s. This means that the marble's velocity will increase by 20 cm/s every second.

Explanation:

hope this helps you find your answer :)

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Which has the largest range in air

laila [671]

I would assume gamma rays because they have the fastest moving partials out of all of them

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3 years ago

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A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot was in view for a total of 0.51 s,

Gelneren [198K]

The pot spends T = 0.185s going up and 0.185s going down past the window.
The average speed passing by the window is 2.20 m/0.185s = 11.89 m/s.
During passage, the pot increases speed by T*g = 0.185*9.81 = 1.815 m/s
The speed is therefore 12.80 m/s at the bottom of the window and 10.98 m/s at the top of the window.

The 10.98 m/s speed at the top of the window allows it to rise another 10.98^2/(2g)= 6.15 m past the top of the window

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3 years ago

Suppose our experimenter repeats his experiment on a planet more massive than Earth, where the acceleration due to gravity is g

tekilochka [14]

Answer: a) It will take more time to return to the point from which it was released

Explanation: To determine how long it takes for the ball to return to the point of release and considering it is a free fall system, we can use the given formula:

$d=v_{0}.t + \frac{1}{2} .a.t^{2}$ , where:

d is the distance the ball go through;

v₀ is the initial velocity, which is this case is 0 because he releases the ball;

a is acceleration due to gravity;

t is the time necessary for the fall;

Suppose <em>h</em> is the height from where the ball was dropped.

On Earth:

h=0.t + $\frac{1}{2}.10.t^{2}$

h = 5t²

$t_{T}$ = $\sqrt{\frac{h}{5} }$

On the other planet:

h = 0.t + $\frac{1}{2}.30.t^{2}$

h = 15.t²

$t_{P}$ = $\sqrt{\frac{h}{15} }$

Comparing the 2 planets:

$\frac{t_{T} }{t_{P} } = \frac{\sqrt{\frac{h}{5} } }\sqrt{{\frac{h}{15} } }$

$\frac{t_{T} }{t_{P} }$ = $\sqrt{3}$ or $t_{T} = \sqrt{3}.t_{P}$

Comparing the two planets, on the massive planet, it will take more time to fall the height than on Earth. In consequence, it will take more time to return to the initial point, when it was released.

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3 years ago

An inductor has an inductance of 0.12 mH. Calculate the number of turns per unit length of this inductor if it has a total of 50

SSSSS [86.1K]

Answer:

Explanation:

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3 years ago

The coefficient of linear expansion of iron is 1.0 × 10−5 per C◦ . The surface area of an iron cube, with an edge length of 5.0

Allushta [10]

The linear expansion of iron is a = 1× 10∧ -5 /°C
Length edge is 5cm
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= 150cm∧²
The edge length of cube after being heated from
10°C to 60°C is
L = L[I +a dt] where the dt is = 60-10 = 50°C
5.0025cm
A surface area of the cube after heated is
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3 years ago