Answer:
The time of Mars is 1.65 times larger on Mars than on Earth
Explanation:
The equation that describes the system is the final speed is equal to the speed minos the speed lost by the collision with the porhole
Vf = Vo - V pothole
B) let's transform the weight of free groin system and N international system
1 N = 0.2248 lb
2.8 lbs (1N / 0.2248lbs) = 12.5 N
c) Kinematic equations are the same in all inertial systems, Mars and Earth, so we can use the height equation, with zero initial velocity
Y = Vo t - ½ g t²
Y = - ½ g t²
t = √ 2Y / g
Mars
gm = 0.37g
gm = 0.37 9.8
gm = 3,626 m / s²
t = √( 2 1.9 / 3.626
)
t = 1.02 s
Earth
t = √( 2 1.9 / 9.8)
t = 0.62 s
To make the comparison of time we are the relationship between the two
tm / te = 1.02 / 0.62
tm / te = 1.65
The time of Mars is 1.65 times larger on Mars than on Earth
The answer is:
71.6 <span>°F</span>
Answer: the lvl wud remain the same
Explanation: as per Archimedes Principle, the weight of the water displaced by the object is equal to the weight of the object. When the ship initially went into the pool, it wud hv displaced some water. When the anchor is dropped, the level does not change coz the anchor was already in the ship and no extra weight has been added, so the weight of the anchor has already been accounted for in the first place when the ship was first placed in the pool
Answer:
16.9000000000000001 J
Explanation:
From the given information:
Let the initial kinetic energy from point A be 
= 1.9000000000000001 J
and the final kinetic energy from point B be 
= ???
The charge particle Q = 6 mC = 6 × 10⁻³ C
The change in the electric potential from point B to A;
i.e. V_B - V_A = -2.5 × 10³ V
According to the work-energy theorem:
-Q × ΔV = ΔK
The current in each experiment increases with increase in the voltage. Similarly, the association between resistance and the current in a circuit shows that increase in the resistance shows a reduction in the current, vice versa.
Ohm's Law states that the voltage across an electric conductor is directly proportional to the current(I) passing through it provided the resistant is constant.
So;
V ∝ I
V = IR
where
The objective of this question want us to determine: How did the current change for each test provided that Avery uses a 1.5-volt battery, then she uses a 3-volt battery and lastly she uses a 9-volt battery, given that the resistance is constant through out the whole process.
In the first experiment;
In the second experiment;
In the third experiment;
Therefore, we can conclude that the current in each experiment increases with increase in the voltage. Similarly, the association between resistance and the current in a circuit shows that increase in the resistance shows a reduction in the current, vice versa.
Learn more about Ohm's Law here:
brainly.com/question/14296509
