Which is bigger 145 m or 145 km
2 answers:
You might be interested in
Answer: Time required to deposit an even layer of gold with given thickness is sec.
Explanation:
The given data is as follows.
Surface area = 49.8 ,
Density of gold = 19.3 ,
Current = 3.15 A, thickness of gold layer =
It is known that relation between volume, area and thickness is as follows.
V = Surface area × Thickness
=
= 0.05988
Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.
= sec
Thus, we can conclude that time required to deposit an even layer of gold with given thickness is sec.
The Structure of Glycine is attached below and each central atom is encircled with different colors.
Molecular Shape around Nitrogen Atom (Orange):
As shown, Nitrogen is making three single bonds with two hydrogen atoms and one carbon atom hence, it has three bonded pair electrons and a single lone pair of electron. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Trigonal Pyramidal.
Molecular Shape around Carbon Atom (Green):
As shown, Carbon is making four single bonds with two hydrogen atoms and one nitrogen atom one with carbon atom of carbonyl group hence, it has four bonded pair electrons. Therefore, according to VSEPR theory it has Tetrahedral geometry.
Molecular Shape around Carbon Atom (Blue):
As shown, Carbon is making two single bonds with oxygen and carbon atoms and a double bond with oxygen. Hence, it has a Trigonal Planar geometry.
Molecular Shape around Oxygen Atom (Red):
As shown, Oxygen is making two single bonds with one carbon atoms and one hydrogen atom hence, it has two bonded pair electrons and two lone pair of electrons. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Bent.
