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3 years ago

Which is bigger 145 m or 145 km

Chemistry

2 answers:

Citrus2011 [14]3 years ago

8 0

145 km i think is bigger

Deffense [45]3 years ago

5 0

145 km, because km = kilometers, and the prefix kilo- means 1,000.

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Explanation:

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2 years ago

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If a gas has a volume of 3.20 L at 273 K, what will be its new volume at 373 K?

jarptica [38.1K]

Answer:

Explanation:

Example #1: How many moles of oxygen will occupy a volume of 2.50 L at STP? Standard ... What is the volume of gas at 2.00 atm and 200.0 K if its original volume was ... P2 = 2.00 atm 2.000tm) 273k. T=273k. 200.0k. Tz= 200.0k. V, = 200.0L ... A gas has a pressure of 0.370 atm at 50.0°C. What is the pressure at standard.

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3 years ago

Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s

bazaltina [42]

Answer: The time taken by the reaction is 84.5 seconds

Explanation:

The equation used to calculate half life for first order kinetics:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{9}=0.077s^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$ ......(1)

where,

k = rate constant = $0.077s^{-1}$

t = time taken for decay process = 50.7 sec

$[A_o]$ = initial amount of the reactant = ?

[A] = amount left after decay process = 0.0741 M

Putting values in equation 1, we get:

$0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}$

$[A_o]=3.67M$

Now, calculating the time taken by using equation 1:

$[A]=0.0055M$

$k=0.077s^{-1}$

$[A_o]=3.67M$

Putting values in equation 1, we get:

$0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s$

Hence, the time taken by the reaction is 84.5 seconds

6 0

3 years ago

3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 m

IrinaK [193]

Answer:

$49.45~%$

Explanation:

In this case, we have to start with the chemical reaction:

$C_6H_1_2O~->~C_6H_1_0~+~H_2O$

So, if we start with 10 mol of cyclohexanol ( $C_6H_1_2O$ ) we will obtain 10 mol of cyclohexanol ( $C_6H_1_0$ ). So, we can calculate the grams of cyclohexanol if we calculate the molar mass: