Chlorine has a atomic number of 17. It often forms an ion by gaining 1 electron. What would it's charge be?

Iron metal reacts with elemental oxygen to form rust according to the unbalanced reaction, Fe(s) + O2(g) → Fe2O3(s),. What is th

pochemuha

Answer:

c. 3

Explanation:

The unbalanced reaction expression is given as:

Fe + O₂ → Fe₂O₃

To balance the expression gives the coefficient of oxygen.

Assign the coefficients a,b, c and use a mathematical approach to solve this problem:

aFe + bO₂ → cFe₂O₃

Conserving Fe: a = 2c

O: 2b = 3c

Now let c = 1, a = 2, b = $\frac{3}{2}$

Multiply through by 2,

a = 4, b = 3 and c = 2

4Fe + 3O₂ → 2Fe₂O₃

The coefficient of O₂ is 3

3 0

2 years ago

The product gas is then passed through a concentrated solution of KOH to remove the CO2. After passage through the KOH solution,

Kamila [148]

<u>Answer:</u> The mass percent of nitrogen gas in the compound is 13.3 %

<u>Explanation:</u>

Assuming the chemical equation of the compound forming product gases is:

$\text{Compound}\xrightarrow[CuO(s)]{Hot}N_2(g)+CO_2(g)+H_2O(g)$

Now, the product gases are treated with KOH to remove carbon dioxide.

We are given:

$p_{Total}=726torr\\P_{water}=23.8torr\\$

So, pressure of nitrogen gas will be = $p_{Total}-p_{water}=726-23.8=702.2torr$

To calculate the number of moles of nitrogen, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of nitrogen gas = 702.2 torr = 0.924 atm (Conversion factor: 1 atm = 760 torr)

V = Volume of nitrogen gas = 31.8 mL = 0.0318 L (Conversion factor: 1 L = 1000 mL)

T = Temperature of nitrogen gas = $25^oC=[25+273]K=298K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

$0.924atm\times 0.0318L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\n_{mix}=\frac{0.924\times 0.0318}{0.0821\times 298}=0.0012mol$

To calculate the mass of nitrogen gas, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.0012 moles

Putting values in above equation, we get:

$0.0012mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.0012mol\times 28g/mol)=0.0336g$

To calculate the mass percent of nitrogen gas in compound, we use the equation:

$\text{Mass percent of nitrogen gas}=\frac{\text{Mass of nitrogen gas}}{\text{Mass of compound}}\times 100$

Mass of compound = 0.253 g

Mass of nitrogen gas = 0.0336 g

Putting values in above equation, we get:

$\text{Mass percent of nitrogen gas}=\frac{0.0336g}{0.253g}\times 100=13.3\%$

Hence, the mass percent of nitrogen gas in the compound is 13.3 %

8 0

3 years ago

What percentage of the mass of 1 mole of CH3Cl is derived from carbon?

steposvetlana [31]

Answer:

Element Symbol Atomic weight Atoms Mass percent

Carbon C 12.0107 1 23.7894

Hydrogen H 1.00794 3 5.9892

Chlorine Cl 35.453 1 70.2213

Explanation:

3 0

3 years ago

Can propanol become oxidised to propanoic acid

shtirl [24]

I’m not 100% sure but I think so

5 0

2 years ago

Read 2 more answers

• If 2.5 moles of sugar are added to 2.0 L of a water/lemon juice solution, what is the molarity of the lemonade?

d1i1m1o1n [39]

The answer is 4.5 because you add rhem

6 0

3 years ago