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Norma-Jean [14]
3 years ago
8

An irreversible reaction is one that:

Chemistry
1 answer:
bazaltina [42]3 years ago
5 0

Answer:

(d) has an extremely large equilibrium constant.

Explanation:

Hello,

Considering a generic chemical reaction:

aA+bB  cC+dD

The equilibrium constant is defined as:

K=\frac{[C]^c_{eq}[D]^d_{eq}}{[A]^a_{eq}[B]^b_{eq}} \\

Now, an irreversible chemical reaction is a reaction in which the reagents are converted into products with no chance of coming back, so, considering the previous chemical reaction, the concentration of both A and B tends to be zero, so an extremely large equilibrium constant is gotten.

Best regards.

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Answer: hope this helps :)

Explanation:

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What is the difference in height between the top surface of the glycerin and the top surface of the alcohol? Suppose that the de
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Here is the full question

Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm until the height of the alcohol column is 10 cm. The two liquids do not mix.

What is the difference in height between the top surface of the glycerin and the top surface of the alcohol? Suppose that the density of glycerin is 1260 kg/m3and the density of alcohol is 790 kg/m3.

Express your answer in two significant figures and include the appropriate units (in cm)

Answer:

ΔH ≅ 3.73 cm

Explanation:

The pressure inside a liquid is known as hydrostatic pressure and which is represent by the formula:

P =   ρ × g × h

where;

ρ is the density of the fluid

g is the gravitational constant

h is the height from the surface

From the question above;

For glycerine; we have:

density of glycerine = 1260 kg/m³

gravitational constant = 9.8 m/s²

height = ???

∴

P_{(g)= 1260kg/m^3}*9.8m/s^2*h_g   ----- equation (1)

On the other hand for alcohol:

density of alcohol is given as = 790 kg/m³

gravitational constant = 9.8 m/s²

height = 10 cm

∴

P_{(a)= 790kg/m^3*9.8m/s^2*10           ----------- equation (2)

if we equate equation 1 and 2 together; we have

P_{(g)= P_{(a)

1260kg/m^3}*9.8m/s^2*h_g = 790kg/m^3*9.8m/s^2*10cm

Making h_g the subject of the formula, we have :

h_g= \frac{ 790kg/m^3*9.8m/s^2*10cm}{1260kg/m^3*9.8m/s^2}

h_g = 6.269 cm

The difference in the height denoted  by ΔH can therefore be calculated as:

ΔH = H_a-H_g

ΔH = 10cm - 6.269cm

ΔH = 3.731 cm

ΔH ≅ 3.73 cm           (to two significant figures)

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