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pantera1 [17]
3 years ago
9

A sample of Francium-212 will decay to one sixteenth of its original amount after 80 minutes. What is the half-life of Francium-

212.
Chemistry
1 answer:
lbvjy [14]3 years ago
6 0

20 minutes.

The sample would lose one half the quantity of francium in each half-life.

1/16 = 1/2^{4} = 1/2 \times1/2 \times1/2 \times1/2

Thus a mass decrease by a factor of 16 would correspond to a period of four half-lives. It took 80 minutes for the sample to lose all these francium, therefore

t_{1/2} = 80/4 = 20 minutes.

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ANSWER

The correct answer is A

EXPLANATION

Plants manufacture their on food by the process of photosynthesis. During this process, plants trap radiant energy from the sun by the help of chlorophyll in the leaves.

Radiant energy with other raw materials such as water, carbon dioxide and mineral salts is converted to food (in the form of starch) which contains chemical energy.
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Modeling Nuclear Processes Quick Check
Valentin [98]

The phrase which best describes nuclear fusion is: A. the process by which small nuclei combine into a larger nucleus.

A nuclear reaction can be defined as a type of chemical reaction in which the nucleus of an atom of a radioactive chemical element is transformed by either being joined (fusion) or split (fission) with the nucleus of another atom of a radioactive chemical element and accompanied by a release of energy.

Generally, there are two (2) main types of nuclear reaction and these include:

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In conclusion, nuclear fusion is best described as the process by which small nuclei combine into a larger nucleus, accompanied by a release of energy.

Read more: brainly.com/question/24040465

4 0
2 years ago
The value of ΔH° for the reaction below is -6535 kJ. ________ kJ of heat are released in the combustion of 16.0 g of C6H6 (l)?
Umnica [9.8K]

Answer:

the value of H° is below -6535 kj. +6H2O

Explanation:

6H2O answer solved

3 0
2 years ago
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
mamaluj [8]

Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

2SO_2 + O_2 \to 2SO_3

The I.C.E table can be represented as:

                     2SO₂              O₂                   2SO₃

Initial:             14                  2.6                     0

Change:        -2x                -x                      +2x

Equilibrium:   14 - 2x          2.6 - x                2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,  

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction 2SO_2 + O_2 \to 2SO_3 = 0.8325;

If we want to find:

SO_2 + \dfrac{1}{2}O_2 \to SO_3

Then:

K_c = (0.8325)^{1/2}

\mathbf{K_c = 0.912}

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

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stiks02 [169]

Answer: Chemical Reaction

Explanation:

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