50 POINTS!!! i'll give BRAINLIEST !

Mathematics

2 answers:

Nesterboy [21]3 years ago

7 0

Step-by-step explanation:

In Exercise B, the complement of an angle is 90° - ∠X

4. 90° - 45° = 45°

5. 90° - 20° = 70°

6. 90° - 30° = 60°

7. 90° - 55° = 35°

8. 90° - 75° = 15°

9. 90° - 80° = 10°

In Exercise C, the supplement of an angle is 180° - ∠X

10. 180° - 20° = 160°

11. 180° - 105° = 75°

12. 180° - 90° = 90°

13. 180° - 150° = 30°

14. 180° - 135° = 45°

15. 180° - 120° = 60°

Setler [38]3 years ago

3 0

Answer:

In Exercise B, the complement of an angle is 90° - ∠X

4. 90° - 45° = 45°

5. 90° - 20° = 70°

6. 90° - 30° = 60°

7. 90° - 55° = 35°

8. 90° - 75° = 15°

9. 90° - 80° = 10°

In Exercise C, the supplement of an angle is 180° - ∠X

10. 180° - 20° = 160°

11. 180° - 105° = 75°

12. 180° - 90° = 90°

13. 180° - 150° = 30°

14. 180° - 135° = 45°

15. 180° - 120° = 60°

Step-by-step explanation:

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The diagram shows a 5 cm x 5 cm x 5 cm cube.

mylen [45]

Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

$\sqrt{a^2+b^2}$

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

$\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}$

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths $a_1, a_2, a_3, \ldots, a_n$ is