The option that has the correct order or sequence of events are;
1) Scan host.
2) Add host to subscription.
3) Use host as report source.
<h3>What are host assets?</h3>
Host assets are known to be a kind of IP addresses in a person's account. This type of assets is one that can be used as a kind of scan, map and also to report targets.
A person can view the hosts in their account by going the Assets panel to the Host Assets. One can add new hosts by the use of the New menu. The person can also only carry out actions like scanning, mapping and reporting on one's hosts.
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Answer:
The answer is blueprint.
Explanation:
Have a nice day or night!
Answer:
Explanation:
The rank of the magnitude of the diffusion coefficient from greatest to least is as follows:
C in Fe at 900°C > Cr in Fe at 900°C > Cr in Fe at 600°C
Reason
C in Fe is an interstitial impurity while Cr in Fe is a substutional impurity.Therefore interstitial impurity occurs in C in Fe systems,while substutitional diffusion occurs in Cr in Fe system.Interstitial is much faster than substitutional diffusion hence the order
Also with increasing temperature magnitude of diffusion coefficient increases,due to the relation.
D = D₀exp(-Qd/RT)
Where D₀=Temperature independent per exponential
Qd= The activation energy for diffusion
R= Universal gas constant
T=absolute temperature
Suppose a tank is made of glass and has the shape of a right-circular cylinder of radius 1 ft. Assume that h(0) = 2 ft corresponds to water filled to the top of the tank, a hole in the bottom is circular with radius in., g = 32 ft/s2, and c = 0.6. Use the differential equation in Problem 12 to find the height h(t) of the water.
Answer:
Height of the water = √(128)/147456 ft
Explanation:
Given
Radius, r = 1 ft
Height, h = 2 ft
Radius of hole = 1/32in
Acceleration of gravity, g = 32ft/s²
c = 0.6
Area of the hold = πr²
A = π(1/32)² ---- Convert to feet
A = π(1/32 * 1/12)²
A = π/147456 ft²
Area of water = πr²
A = π 1²
A = π
The differential equation is;
dh/dt = -A1/A2 √2gh where A1 = Area of the hole and A2 = Area of water
A1 = π/147456, A2 = π
dh/dt = (π/147456)/π √(2*32*2)
dh/dt = 1/147456 * √128
dh/dt = √128/147456 ft
Height of the water = √(128)/147456 ft