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3 years ago

B. How many molecules are in 25.0 grams of H2SO4?

Chemistry

1 answer:

Firdavs [7]3 years ago

4 0

Answer:

4.23 x 10^-25 molecules

Explanation:

$25.0 g H2SO (\frac{1 mol H2SO4}{98.1 g H2SO4}) (\frac{6.023x10^{23} molecules}{1 mol H2SO4} ) = 4.23 x10^-25 molecules$

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Sn + 2 H2SO4 → SnSO4 + SO2 + 2 H2O If 219.65 grams of SnSO4 are produced, how many moles of H2SO4 were reacted?

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Answer:

2.05moles

Explanation:

The balanced chemical equation in this question is as follows;

Sn + 2H2SO4 → SnSO4 + SO2 + 2H2O

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How many grams of solid NaOH are required to prepare a 400ml of a 5N solution? show your work!

Nuetrik [128]

<u>Answer:</u> The mass of solid NaOH required is 80 g

<u>Explanation:</u>

Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

$\text{Equivalent weight}=\frac{\text{Molecular weight}}{n}$

where,

n = acidity for bases = 1 (For NaOH)

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Putting values in above equation, we get:

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$\text{Normality of solution}=\frac{\text{Number of gram equivalents} \times 1000}{\text{Volume of solution (in mL)}}$

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$\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}$ ......(1)

We are given:

Given mass of NaOH = ?

Equivalent mass of NaOH = 40 g/eq

Volume of solution = 400 mL

Normality of solution = 5 eq/L

Putting values in equation 1, we get:

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