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Goshia [24]
3 years ago
6

B. How many molecules are in 25.0 grams of H2SO4?

Chemistry
1 answer:
Firdavs [7]3 years ago
4 0

Answer:

4.23 x 10^-25 molecules

Explanation:

25.0 g H2SO (\frac{1 mol H2SO4}{98.1 g H2SO4}) (\frac{6.023x10^{23}  molecules}{1 mol H2SO4} ) = 4.23 x10^-25 molecules

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Calculate the theoretical yield of benzoin assuming you begin with 13.7 mL of benzaldehyde and assuming that the density of benz
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4 years ago
A solution of the primary standard potassium hydrogen phthalate (KHP), KHC8H4O4 , was prepared by dissolving 0.4877 g of KHP in
Grace [21]

Answer:

The concentration of KOH is  0.06137 M

Explanation:

Step 1: Data given

Molar mass of KHP = 204.22 g/mol

Mass of KHP = 0.4877 grams

Volume of water = 50 mL

Volume of KOH solution = 38.91 mL

Step 2: The balanced equation

C8H5KO4 + KOH ⇒ C8H4K2O4+ H2O

Step 3: Calculate number of moles of KHP

Moles = Mass / molar mass

Moles KHP = 0.4877 grams / 204.22 g/mol

Moles KHP = 0.002388 moles

Step 4: Calculate moles of KOH

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For 0.002388 moles KHP we need 0.002388 moles KOH

Step 5: Calculate the concentration of KOH

Concentration = moles / volume

Concentration of KOH = 0.002388 moles / 0.03891 L

Concentration of KOH = 0.06137 M

The concentration of KOH is  0.06137 M

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