Answer:
a) W = 3.87 10⁻⁴ J
, b) P = 3.10 10⁻³ Pa
, c) λ = 671. 6 nm
, d) frequency does not change
, e) Emax = 1.39 C / m and f) Bmax = 4.7 10⁻⁹ T
Explanation:
a) Let's use the concepts of power that is work for the unit of time and work is the change of kinetic energy
P = W / t
An electromagnetic wave has an intensity
I = P / A =
W = P t
W = 258 10⁻³ 1.5 10⁻³
W = 3.87 10⁻⁴ W s
W = 3.87 10⁻⁴ J
b) the radiation pressure is given by the ratio
P = I / c
Where I is the intensity
I = Powers / A
A = π r² = π (d/2)²
I = 258 10⁻³ / π (297.5 10⁻⁶)²
I = 9.29 10 5 W / m²
P = 9.29 10⁵/3 10⁸
P = 3.10 10⁻³ Pa
c) The wavelength when passing a measured of different refractive index changes in the way
λ = λ₀ / n
λ = 900 10⁻⁹ / 1.34
λ = 671.6 10⁻⁹ m
λ = 671. 6 nm
d) when the light strikes a medium creates a forced oscillation in the electrons of the medium, this is a resonance phenomenon, so the frequency does not change
e) The maximum electric field is
I = Emax2 / 2 μ₀ c
Emax = Ra (2 μ₀ c I)
Emax = Ra (2 4 π 10⁻⁷ 3 10⁸ 258 10⁻³)
Emax = 1.39 C / m
f) the elective and magnetic fields are related
c = Emax Bmax
Bmax = Emax / c
Bmax = 1.39 / 3 10⁸
Bmax = 4.7 10⁻⁹ T
Answer:
if the image is on the book yes , no its can be both
Explanation:
<span>Psychological researchers must debrief human test subjects </span><span>at the end of every experiment.
The current code of ethics in p</span>sychological research states that researchers absolutely must debrief human test subjects at the end of every study regardless or whether or not harm or deception was involved.
Debriefing a subject after a study is an essential opportunity for the researcher to explain the purpose and aim of the study to the subject, make sure the subject is not harmed or mentally disturbed, clarify why deception was used (if deception was involved) and overall, to clarify any questions or doubts the subject might have.
Answer:
hart beats in 0.8s=1
heart beat in 1s= 1/0.8
70 years=2207520000s
heart beat in 70years(2207520000s)=1.25x2207520000
=2759400000times
Explanation: