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olga55 [171]
3 years ago
15

Lactic acid is produced during low-moderate exercise True False

Physics
2 answers:
patriot [66]3 years ago
7 0
True. 

       Hope this helps!!
Marizza181 [45]3 years ago
3 0
The answer to your question is true.
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The frequency of a wave is 250hz. What is the period
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2 years ago
The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of g
Morgarella [4.7K]

Here is the full question:

The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent hoop about that axis, if the hoop has the same mass M and a radius k given by:  

k=\sqrt{\frac{I}{M} }

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of gyration of (a) a cylinder of radius 1.20 m, (b) a thin spherical shell of radius 1.20 m, and (c) a solid sphere of radius 1.20 m, all rotating about their central axes.

Answer:

a) 0.85 m

b) 0.98 m

c) 0.76 m

Explanation:

Given that: the radius of gyration  k=\sqrt{\frac{I}{M} }

So, moment of rotational inertia (I) of a cylinder about it axis = \frac{MR^2}{2}

k=\sqrt{\frac{\frac{MR^2}{2}}{M} }

k=\sqrt{{\frac{MR^2}{2}}* \frac{1}{M} }

k=\sqrt{{\frac{R^2}{2}}

k={\frac{R}{\sqrt{2}}

k={\frac{1.20m}{\sqrt{2}}

k = 0.8455 m

k ≅ 0.85 m

For the spherical shell of radius

(I) = \frac{2}{3}MR^2

k = \sqrt{\frac{\frac{2}{3}MR^2}{M}  }

k = \sqrt{\frac{2}{3} R^2}

k = \sqrt{\frac{2}{3} }*R

k = \sqrt{\frac{2}{3}}  *1.20

k = 0.9797 m

k ≅ 0.98 m

For the solid sphere of  radius

(I) = \frac{2}{5}MR^2

k = \sqrt{\frac{\frac{2}{5}MR^2}{M}  }

k = \sqrt{\frac{2}{5} R^2}

k = \sqrt{\frac{2}{5} }*R

k = \sqrt{\frac{2}{5}}  *1.20

k = 0.7560

k ≅ 0.76 m

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3 years ago
What types of evidence are used to support The Big Bang theory?
andriy [413]

Answer:

Hubble's Discovery

cosmic microwave background radiation

4 0
3 years ago
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A small bar of pure gold whose density is 19.3g/cm. Displaces 80 cm
nasty-shy [4]

Answer:

The mass of the gold bar is 1,544 g

Explanation:

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2 years ago
A motorcycle has a mass of 350kg. A force of 1295N is applied to the cycle what is the motorcycles acceleration
Maru [420]

Answer: 3.7 m/s^2

Explanation:

The acceleration of the motorcycle is given by Newton's second law:

a=\frac{F}{m}

where

F = 1295 N is the force applied to the motorcycle

m = 350 kg is the mass of the motorbike

a is the acceleration

By substituting the numbers into the formula, we find

a=\frac{F}{m}=\frac{1295 N}{350 kg}=3.7 m/s^2

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3 years ago
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