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schepotkina [342]
2 years ago
11

What happens to a decimal place in the number when you are converting from a smaller metric unit to a larger unit?

Physics
1 answer:
Natasha_Volkova [10]2 years ago
6 0

I dont have any idea :P

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Two identical carts are free to move along a straight frictionless track. At time t1, cart X is moving at 2.0 m/s when it collid
jarptica [38.1K]

Answer:

Explanation:

Using the law of conservation of momentum;

m_1 u_1+m_2u_2 = m_1v_1+m_2v_2

here;

There is a need for conservation of the total momentum that occurred before and after the collision.

So;

m_1 = mass of cart X

m_2 = mas 9f cart Y

u_1 = velocity of cart X (before collision)

u_2 = velocity of cart Y (before collision)

v_1 = velocity of cart X (after collision)

v_2 = velocity of cart Y (after collision)

So;

m(u_1+0) =(m_1v+m_2)v

because the mass is identical and v represents the velocity of both carts.

Now;

u_1 = 2 m/s

u_2 = 0 ( at rest)

∴

m(2) = (2m)v

v = 1 m/s

Thus, we can see from the graphical image attached below that the velocity of X reduces to 1 m/s after collision with cart Y.

8 0
3 years ago
Which of the following best describes electromagnetic waves?
luda_lava [24]

Electromagnetic waves are waves characterized by oscillating coupled electric and magnetic fields (electromagnetic fields). Because these are waves, they are shown to exhibit wave phenomena such as diffraction, reflection, and transmission, much like other types of waves.

The best description looks like option D

5 0
1 year ago
How could you increase the force advantage of a lever?Select one:a. Make the effort length longer.b. Make the effort length shor
11Alexandr11 [23.1K]

The ideal mechanical advantage of a lever (IMA) is given by:

IMA=\frac{Le}{Lr}

Where:

Le = Effort of the arm

Lr = Resistance arm.

Therefore, we can increase the force adventage by increasing the effort arm or reducing the load arm

Answer:

a. Make the effort length longer.

4 0
9 months ago
A 58 g firecracker is at rest at the origin when it explodes into three pieces. The first, with mass 12 g , moves along the x ax
alexdok [17]

Answer:

Explanation:

We shall apply conservation of momentum law in vector form to solve the problem .

Initial momentum = 0

momentum of 12 g piece

= .012 x 37 i since it moves along x axis .

= .444 i

momentum of 22 g

= .022 x 34 j

= .748 j

Let momentum of third piece = p

total momentum

= p + .444 i + .748 j

so

applying conservation law of momentum

p + .444 i + .748 j  = 0

p = - .444 i -  .748 j  

magnitude of p

= √ ( .444² + .748² )

= .87 kg m /s

mass of third piece = 58 - ( 12 + 22 )

= 24 g = .024 kg

if v be its velocity

.024 v = .87

v = 36.25 m / s .

6 0
2 years ago
*<br> Check all of the things that can affect power<br><br> Time<br> Work<br> Distance<br> Force
gladu [14]

Answer:

fhddmvxmvydlyghclhchc

3 0
2 years ago
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