80% from burning fossil fuels
Answer:
The time taken by the car to get to the other side of an intersection is, t = 4.9 s
Explanation:
Given data,
The acceleration of the car, a = 2.5 m/s²
The initial velocity of the car, u = 0
The distance traveled, s = 30 m
Using the II equations of motion,
<em> S = ut + ½ at²</em>
Therefore,
t = √(2S/a) ( since u = 0)
Substituting the values
t = √(2 x 30 / 2.5)
= 4.9 s
Hence, the time taken by the car to get to the other side of an intersection is, t = 4.9 s
Answer:
Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:
Explanation:
Answer:
F= 4788 N
Explanation:
Because the car moves with uniformly accelerated movement we apply the following formula:
vf²=v₀²+2*a*d Formula (1)
Where:
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
d=36.9 m
v₀=14.0 m/s m/s
vf= 0
Calculating of the acceleration of the car
We replace dta in the formula (1)
vf²=v₀²+2*a*d
(0)²=(14)²+2*a*(36.9)
-(14)²= (73.8) *a
a= - (196) / (73.8)
a= - 2.66 m/s²
Newton's second law of the car in direction horizontal (x):
∑Fx = m*ax Formula (2)
∑F : algebraic sum of the forces in direction x-axis (N)
m : mass (kg)
a : acceleration (m/s²)
Data
m=1800 Fkg
a= - 2.66 m/s²
Magnitude of the horizontal net force (F) that is required to bring the car to a halt in a distance of 36.9 m :
We replace data in the formula (2)
-F= (1800 kg) * ( -2.66 m/s²
)
F= 4788 N
Basic division, divide 100km by 10 and you get the average speed of the ship.
10 Km/s
you do need the distance traveled and the time it took to travel that distance for this method