1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksley [76]
3 years ago
10

In solving for the magnitude of the electric field E⃗(z) produced by a sheet charge with charge density σ, use the planar symmet

ry since the charge distribution doesn't change if you slide it in any direction of xy plane parallel to the sheet. Therefore at each point, the electric field is perpendicular to the sheet and must have the same magnitude at any given distance on either side of the sheet. To take advantage of these symmetry properties, use a Gaussian surface in the shape of a cylinder with its axis perpendicular to the sheet of charge, with ends of area A which will cancel out of the expression for E(z) in the end. The result of applying Gauss's law to this situation then gives an expression for E(z) for both z>0 and z<0. (Figure 3) Express E(z) for z>0 in terms of some or all of the variables/constants σ, z, and ϵ0.

Physics
1 answer:
ankoles [38]3 years ago
7 0

Answer:

Check the explanation

Explanation:

Let the charge sheet passes through the middle of the cylinder’s length <em><u>(which is the distance around the end circles)</u></em>, along z-axis, so the cylinder is perpendicular to the surface. Hence the flux through each end will be.....

kindly check the attached image to see the full explanation to the above question.

You might be interested in
Dolphin echolocation is similar to ultrasound. Reflected sound waves
s344n2d4d5 [400]

Answer:

Waves with high frequencies have shorter wavelengths that work better  than low frequency waves for successful echolocation.

Explanation:

To understand why high-frequency waves work better  than low frequency waves for successful echolocation, first we have to understand the relation between frequency and wavelength.

The relation between frequency and wavelength is given by

λ = c/f

Where λ is wavelength, c is the speed of light and f is the frequency.

Since the speed of light is constant, the wavelength and frequency are inversely related.

So that means high frequency waves have shorter wavelengths, which is the very reason for the successful echolocation because waves having shorter wavelength are more likely to reach and hit the target and then reflect back to the dolphin to form an image of the object.

Thus, waves with high frequencies have shorter wavelengths that work better  than low frequency waves for successful echolocation.

3 0
3 years ago
What do you mean by kinetic energy and potential energy ?
Verizon [17]

  • Kinetic Energy of an object is the measure of the work an object can do by virtue of its motions..

  • Formula - KE = 1/2 mv^2

  • Where KE is the kinetic energy, m is the body’s mass, and v is the body’s velocity.

  • Potential energy is the stored energy in any object or system by virtue of its position or arrangement of parts..

  • Formula - W = mgh

Where,

. m is the mass in kilograms

. g is the acceleration due to gravity

. h is the height in meters

Hope it helpz~ uh..

4 0
1 year ago
Can someone solve this problem and explain to me how you got it​
evablogger [386]

Answer:

question5: F=74312.5N

question6: charge at the end of antenna=0.37N

Explanation:

Coulomb's law: the magnitude of the force of attraction or repulsion due to two charges is proportional to the product of the magnitude of the charges and inversely proportional to the square of distance between the charges.

⇒F\alpha\frac{q1*q2}{r^{2}}

∴F=k\frac{q1*q2}{r^{2}}

where F is the force of attraction or repulsion

k is Coulumb's constant=9*10^{9}Nm^{2}C^{-2}

q1 and q2 are the magnitude of the charges

r is the distance between two charges

The force between the two charges is attractive if they are of different polarity

The force between the two charges is repulsive if they are of same polarity

Question5:

Given: q1=0.041 C, q2=0.029 C, r=12 m

therefore by Coulumb's law,

F=9*10^{9}*\frac{0.041*0.029}{12^{2}}

F=74312.5N

Question6:

Given: q1=3*10^{-18}C, r=5 m, F=4*10^{-11}N

therefore by Coulumb's law,

4*10^{-11}=9*10^{9}*\frac{3*10^{-18}*q2}{5^{2}}

⇒q2=\frac{4*10^{-11}*25}{9*10^{9}*3*10^{-18}} \\=0.37C

4 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> I NEED THE ANSWER NOW
FrozenT [24]
90 F = 43 OR 0.9F = 0.43
(F = 43 / 90 OR 0.43 / 0.9 =) 0.48 N

upwards force = downwards force
(R =) 1.2 N
5 0
3 years ago
Planets move around the sun in elliptical orbits. True. False
astra-53 [7]

this answer is true.

5 0
3 years ago
Read 2 more answers
Other questions:
  • At a fixed depth within a fluid at rest, the pressure pushing upward is
    10·1 answer
  • The product nuclei may or may not be _______
    15·1 answer
  • How does the balloon react to the cloth item?
    14·1 answer
  • What does the symbol for Monday mean???
    6·1 answer
  • The difference between speed and velocity is that velocity includes.
    7·2 answers
  • The velocity of a sky diver t seconds after jumping is given by v(t) = 80(1 − e−0.2t). After how many seconds is the velocity 65
    11·1 answer
  • Place least complex to most complex:
    5·1 answer
  • The results from Rutherford's alpha particle scattering experiment led to
    9·1 answer
  • a 1. You found that the MCB was tied with a thread and the thread was fixed with a nail on the wall in your friend's house. i. I
    6·1 answer
  • For a 1 efficient step down transformer voltage in primary and secondary are equal current in primary and secondary are equal in
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!