Question

What is the molarity of a KF(aq) solution containing 3.0 mol of KF in 2.00L of solution?

Answer 1

Answer : The molarity of $KF$ in the solution is 1.5 M.

Explanation : Given,

Moles of $KF$ = 3.0 mol

Volume of solution = 2.00 L

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of }KF}{\text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{3.0mol}{2.00L}=1.5mole/L=1.5M$

Therefore, the molarity of $KF$ in the solution is 1.5 M.