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3 years ago

12

The majority of earthquakes worldwide occur at all but one location. That is A)at tectonic plate boundaries.B)where sediments de

posit and form new layers.C)where plates stick and then jump past each other.D)where an ocean plate slides under a continental plate.

1 answer:

DENIUS [597]3 years ago

6 0

Answer:b

Explanation:

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A pail of water is rotated in a vertical circle of radius r = 1.6 m . The acceleration of gravity is 9.8 m/s 2 . r v What is the

Snowcat [4.5K]

Answer:3.95 m/s

Explanation:

Given

radius of circle $r=1.6 m$

Water will not spill if the centripetal acceleration is greater than acceleration due to gravity

i.e. $a_c\geq g$

$a_c=\frac{v^2}{r}$

$\frac{v^2}{r}\geq g$

$v_{min}=\sqrt{gr}$

$v_{min}=\sqrt{9.8\times 1.6}$

$v_{min}=\sqrt{15.68}$

$v_{min}=3.95 m/s$

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3 years ago

Two identical spheres with m=3 kg each are rigidly attached to the rotating light rigid structure. The velocity of the spheres i

Dennis_Churaev [7]

Answer:

Angular momentum of the system is 4.8 kg m^2/s

Explanation:

As we know that the angular momentum of the system of masses is given as

$L = 2I\omega$

here we have

$I = m(0.2 + 0.4)^2$

$I = 3(0.6)^2$

now we also know that

$\omega = \frac{v}{0.2 + 0.4}$

$0.6 \omega = 2 m/s$

now we have

$L = 2(2)(0.6)(2)$

$L = 4.8 kg m^2/s$

3 0

3 years ago

How do motion and Newton's laws apply to your everyday life?

Marina86 [1]

When you jumó ur legs put force on ground

6 0

3 years ago

A 2-kW electric heater takes 15 min to boil a quantity of water. If this is done once a day and power costs 10 cents per kWh, wh

frozen [14]

Answer:

<h2> $1.50</h2>

Explanation:

Given data

power P= 2 kW

time t= 15 min to hours = 15/60= 1/4 h

cost of power consumption per kWh= 10 cent = $0.1

We are expected to compute the cost of operating the heater for 30 days

but let us computer the energy consumption for one day

Energy of heater for one day= 2* 1/4 = 0.5 kWh

the cost of operating the heater for 30 days= 0.5*0.1*30= $1.50

<u><em>Hence it will cost $1.50 for 30 days operation</em></u>

4 0

3 years ago

Two 60 cm parallel disks are separated by 40 cm and are aligned directly on top of each other. Both disks are black surfaces wit

Crazy boy [7]

Answer:

775.48 W

Explanation:

given,

diameter of disk = 0.6 cm

length of the disk = 0.4 m

T₁ = 450 K T₂ = 450 K T₃ = 300 K

$\dfrac{d}{r_1}=\dfrac{0.4}{0.3}$ = 1.33

now,

the value of view factor (F₁₂)corresponding to 1.33

F₁₂ = 0.265

F₁₃ = 1 - 0.265 = 0.735

now,

net rate of radiation heat transfer from the disk to the environment:

$=\dot{Q_{1-3}+Q_{2-3}} = 2 \dot{Q_{1-3}}$

= 2 F₁₃ A₁ σ (T₁⁴ - T₃⁴)

= 2 x 0.735 x π x (0.3)² x (5.67 x 10⁻⁸ W/m²) (450⁴ - 300⁴)

= 775.48 W

Net radiation heat transfer from the disks to the environment = 775.48 W

3 0

4 years ago