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3 years ago

What do you think happens to the temperature when water changes to gas?

Physics

1 answer:

Olenka [21]3 years ago

5 0

Answer:

it gets hot and more hot until it turns to gas

Explanation:

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Two objects are dropped from rest from the same height. Object A falls through a distance Da and during a time t, and object B f

stiv31 [10]

Answer:

Da=(1/4)Db

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

When s = Da, t = t

$s=ut+\frac{1}{2}at^2\\\Rightarrow Da=0\times t+\frac{1}{2}\times a\times t^2\\\Rightarrow Da=\frac{1}{2}at^2$

When s = Db, t = 2t

$s=ut+\frac{1}{2}at^2\\\Rightarrow Da=0\times t+\frac{1}{2}\times a\times (2t)^2\\\Rightarrow Db=\frac{1}{2}a4t^2$

Dividing the two equations

$\frac{Da}{Db}=\frac{\frac{1}{2}at^2}{\frac{1}{2}a4t^2}=\frac{1}{4}\\\Rightarrow \frac{Da}{Db}=\frac{1}{4}\\\Rightarrow Da=\frac{1}{4}Db$

Hence, Da=(1/4)Db

3 0

3 years ago

An object of unknown mass is initially at rest and dropped from a height h. It reaches the ground with a velocity v1 . The same

Hatshy [7]

Answer:

$v_2=\sqrt{2}v_1$

Explanation:

The velocity v₁ can be calculated with the kinematic formula:

$v_1^{2} =v_0^{2} +2gh$

Since the object is initially at rest, v₁ becomes:

$v_1=\sqrt{2gh}$

Where g is the acceleration due to gravity. Now, the velocity v₂ can be calculated with the same formula, but now the initial velocity is v₁:

$v_2^{2}=v_1^{2} +2gh$

Substituting v₁ in this expression and solving for v₂, we get:

$v_2^{2}=(\sqrt{2gh} )^{2} +2gh=4gh\\\\\implies v_2=\sqrt{4gh}=2\sqrt{gh}$

Now, dividing v₂ over v₁, we get the expression:

$\frac{v_2}{v_1}=\frac{2\sqrt{gh} }{\sqrt{2gh}}=\sqrt{2}\\ \\\implies v_2=\sqrt{2}v_1$

It means that v₂ is √2 times v₁.

4 0

3 years ago

Lus

patriot [66]

Answer:

hey but the person at the top is right

7 0

3 years ago

The current supplied by a battery as a function of time is ) -(0.64 A)e-/(6.0 hr). What is the total number of electrons transpo

Paha777 [63]

Answer:

The total number of electrons is $8.6\times10^{22}$

(3) is correct option.

Explanation:

Given that,

The current equation is

$I=0.64 e^{\dfrac{-t}{6.0 hr}}$

We know that,

The formula of charge

$q=\int_{0}^{\infty}{I dt}$

$q=\int_{0}^{\infty}{0.64 e^{\dfrac{-t}{6.0 hr}}dt$

$q=0.64\int_{0}^{\infty}{e^{\dfrac{-t}{6.0 hr}}dt$

$q=0.64\int_{0}^{\infty}{e^{\dfrac{-t}{21600}}dt$

$q=0.64(21600e^{\dfrac{-t}{21600}})_{0}^{\infty}$

$q=0.64(0-21600)$

$q=0.64\times21600$

$q=13824\ C$

We need to calculate the number of electron

Using formula of charge

$q=ne$

$n=\dfrac{q}{e}$

$n=\dfrac{13824}{1.6\times10^{-19}}$

$n=8.6\times10^{22}$

Hence, The total number of electrons is $8.6\times10^{22}$

7 0

3 years ago

Como se dice casa en náhuatl

Serhud [2]

Answer:

Chāntli

Explanation:

6 0

2 years ago