Which of the following objects is accelerating?

Physics

2 answers:

alexdok [17]2 years ago

4 0

The car on the curve (its direction is changing) and the falling flower pot (its speed is changing) are both undergoing acceleration.

Schach [20]2 years ago

3 0

Answer: A flower pot falling

Explanation:

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5. If a spring with a 40 N/m spring constant is used to push a 10 kg ball to a speed of 2 m/s,

kolbaska11 [484]

By compressing the spring a distance x (in m), you are storing 1/2 k x ² (in J) of potential energy, which is converted completely into kinetic energy 1/2 m v ², where

• k = 40 N/m = spring constant

• m = 10 kg = mass of the ball

• v = 2 m/s = ball's speed (at the moment the spring returns to its equilibrium point)

So we have

1/2 k x ² = 1/2 m v ²

x = √(m/k v ²) = √((10 kg) / (40 N/m) (2 m/s)²) = 1 m

3 0

2 years ago

The annoying sound from a mosquito is produced when it beats its wings at the average rate of 600. wingbeats per second. What is

Svetach [21]

Wavelength = (speed) / (frequency)

Wavelength = (340 m/s) / (600 /s)

Wavelength = 0.567 meter

6 0

3 years ago

The magnetic field at the center of a 1.0-cm-diameter loop is 2.5 mT.

olga nikolaevna [1]

Answer:

(a) The current in the wire is 19.89 A

(b) The distance from the wire is 0.159 cm

Explanation:

Given;

magnetic field, B = 2.5 mT

diameter of the wire, d = 1 cm

radius of the wire, r = 0.5 cm = 0.005 m

(a) The current in the wire is calculated as;

$I = \frac{2Br}{\mu_0} \\\\I = \frac{2\times 2.5 \times 10^{-3} \times 0.005 }{4\pi \times 10^{-7} } \\\\I = 19.89 \ A$

(b) The distance from the wire where the magnetic field is 2.5 mT is calculated as;

$B = \frac{\mu_0 I}{2\pi d} \\\\where;\\\\d \ is \ the \ distance \ from \ the \ wire\\\\d = \frac{\mu_0 I}{2\pi B} = \frac{4 \pi \times 10^{-7} \times 19.89}{2\pi \times 2.5 \times 10^{-3}} = 0.00159 \ m = 0.159 \ cm$