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Svet_ta [14]
3 years ago
5

A train travels north at a speed of 50 m/s.

Physics
1 answer:
Gala2k [10]3 years ago
8 0

The apparent velocity is B) 48 m/s north

Explanation:

Here we have a problem of relativity of velocities.

In fact, the train is travelling north at a speed of

v_t = 50 m/s

where this velocity is measured with respect to the ground.

At the same time, a passenger on the train is walking towards the rear (so, south) at a velocity of

v'=2 m/s

where this velocity is measured with respect to the train, which is in motion in the opposite direction.

Therefore, the apparent velocity of the passenger with respect to an observer standing on the ground is:

v=V_t - v' = 50 - 2 = 48 m/s

And the direction is north, since this number is positive.

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

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A piston-cylinder device initially contains 0.08 m3 of nitrogen gas at 150 kPa and 200°C. The nitrogen is now expanded to a pres
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Answer:

V_2 = 0.125 m^3

Work done =  = 5 kJ

Explanation:

Given data:

volume of nitrogen v_1 = 0.08 m^3

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work done = \frac{P_1 V_1 -P_2 V_2}{n-1}

= \frac{150 \times 0.8 - 80 \times 0.125}{1.4-1}

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