The apparent velocity is B) 48 m/s north
Explanation:
Here we have a problem of relativity of velocities.
In fact, the train is travelling north at a speed of
where this velocity is measured with respect to the ground.
At the same time, a passenger on the train is walking towards the rear (so, south) at a velocity of
where this velocity is measured with respect to the train, which is in motion in the opposite direction.
Therefore, the apparent velocity of the passenger with respect to an observer standing on the ground is:
And the direction is north, since this number is positive.
Learn more about velocity:
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Answer:
Speed of the boat, v = 4.31 m/s
Explanation:
Given that,
Height of the bridge, h = 32 m
The model boat is 11 m from the point of impact when the key was released, d = 11 m
Firstly, we will find the time needed for the boat to get in this position using second equation of motion as :
Here, u = 0 and a = g
t = 2.55 seconds
Let v is the speed of the boat. It can be calculated as :
v = 4.31 m/s
So, the speed of the boat is 4.31 m/s. Hence, this is the required solution.
Answer:
See attached file :)
Hope this helps!
All the love, Ya boi Fraser :)
