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3 years ago

14

write down the total momentum for two marbles of mass,m, both moving at velocity, v. What is the kinetic energy of the system.

2 answers:

denis-greek [22]3 years ago

6 0

The momentum of marble-A is (m v).
The momentum of marble-B is (m v)
Momentum is a vector quantity, and we don't know the direction
either marble is moving. So we don't know how their momenta
will combine. The sum of their momenta is something between
zero and (2mv).

The kinetic energy of marble-A is (1/2 m v²).
The kinetic energy of marble-B is (1/2 m v²).
If the marbles are the only matter in the system, then
the total kinetic energy in the system is (m v²).

frosja888 [35]3 years ago

4 0

Mv + mv = 2mv providing each momentum is in the same direction.
1/2 mv^2 + 1/2 mv^2 = mv^2

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3 years ago

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