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Rasek [7]
3 years ago
14

write down the total momentum for two marbles of mass,m, both moving at velocity, v. What is the kinetic energy of the system.

Physics
2 answers:
denis-greek [22]3 years ago
6 0

The momentum of marble-A is (m v).
The momentum of marble-B is (m v)
Momentum is a vector quantity, and we don't know the direction
either marble is moving.  So we don't know how their momenta 
will combine.  The sum of their momenta is something between
zero and (2mv).

The kinetic energy of marble-A is (1/2 m v²).
The kinetic energy of marble-B is (1/2 m v²).
If the marbles are the only matter in the system, then
the total kinetic energy in the system is (m v²). 
frosja888 [35]3 years ago
4 0
Mv + mv = 2mv providing each momentum is in the same direction.
1/2 mv^2 + 1/2 mv^2  = mv^2
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A load of 500 N is placed 8 N from the pivot what is the turning moment of the load
Nataliya [291]
The answer is 4000N...
6 0
3 years ago
The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.
Sholpan [36]

The frequency of rotation of Mars is 0.0000113 Hertz.

<u>Given the following data:</u>

  • Period = 1 day and 37 minutes.

To find the frequency of rotation in Hertz:

First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.

<u>Conversion:</u>

1 day = 24 hours

24 hours to minutes = 60 × 24 = 1440 minutes

1440 + 37 = 1477 \; minutes

1 minute = 60 seconds

1477 minute = X seconds

Cross-multiplying, we have:

X = 60 × 1477

X = 88620 seconds

Now, we can find the frequency of rotation of Mars by using the formula:

Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}

<em>Frequency </em><em>of rotation</em> = <em>0.0000113 Hertz</em>

Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.

Read more: brainly.com/question/14708169

8 0
2 years ago
Could anyone help me for this question please!! Really emergency!!!
kodGreya [7K]
16/9 m/s^2
negative 4/3 m/s^2
14 m/s
the last one is too detailed to do in my head while on the bus; sorry
5 0
3 years ago
Kelli weighs 440 N, and she is sitting on a playground swing that hangs 0.41 m above the ground. Her mom pulls the swing back an
kifflom [539]

Answer:

Explanation:

Initial height from the ground = .41 m

Final height = 1m

Height by which Kelli was raised ( h )= .59 m

When she passes through the lowest point , she loses P E

= mgh

= 440 x .59

= 259.6 J

kinetic energy possessed by her

= 1/2 mv²

= .5 x (440/9.8) x 2²

= 89.8 J

Difference of energy is lost due to work by  air friction

work done by  friction = 89.8 - 259.6

= - 169.8 J

4 0
3 years ago
A 3.00-kg rifle fires a 0.00500-kg bullet at a speed of 300 m/s. Which force is greater in magnitude:(i) the force that the rifl
alekssr [168]

Answer:

C. both forces have the same magnitude

Explanation:

Here the action force is equal to the reaction force in accordance with the Newton's third law of motion.

Also when we apply the conservation of momentum so that the momentum bullet and the momentum of the gun are equal and according to the second law of motion by Newton, we have force equal to the rate of change in momentum.

We have the equation for momentum as:

p=m.v

Newton's second law is Mathematically given as:

F=\frac{dp}{dt}

Momentum is constant and the reaction time is equal, so the force exerted will also be equal.

7 0
2 years ago
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