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2 years ago

write down the total momentum for two marbles of mass,m, both moving at velocity, v. What is the kinetic energy of the system.

2 answers:

6 0

The momentum of marble-A is (m v).
The momentum of marble-B is (m v)
Momentum is a vector quantity, and we don't know the direction
either marble is moving. So we don't know how their momenta
will combine. The sum of their momenta is something between
zero and (2mv).

The kinetic energy of marble-A is (1/2 m v²).
The kinetic energy of marble-B is (1/2 m v²).
If the marbles are the only matter in the system, then
the total kinetic energy in the system is (m v²).

frosja888 [35]2 years ago

4 0

Mv + mv = 2mv providing each momentum is in the same direction.
1/2 mv^2 + 1/2 mv^2 = mv^2

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2 years ago

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2 years ago

A solenoid that is 78.8 cm long has a cross-sectional area of 15.9 cm2. There are 914 turns of wire carrying a current of 8.25 A

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(a) Energy density will be equal to $57.31J/m^3$

(b) Total energy will be equal to 0.0718 J

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It is given that length of solenoid l = 78.8 cm = 0.788 m

Cross sectional area $A=15.9cm^2=15.9\times 10^{-4}m^2$

Number of turns of the wire N = 914

Current in the solenoid i = 8.25 A

Inductance of the wire is equal to $L=\frac{\mu _0N^2A}{l}=\frac{4\pi \times 10^{-7}\times 914^2\times 15.9\times 10^{-4}}{0.788}=2.117\times 10^{-3}H$

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(a) Energy density will be equal to

$U_b=\frac{0.0718}{15.9\times 10^{-4}\times 0.788}=57.31J/m^3$

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