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expeople1 [14]
3 years ago
15

A 20-gauge shell is placed in a 12-gauge shotgun. What is the danger?

Physics
1 answer:
n200080 [17]3 years ago
5 0

Answer:

If 20 gauge shell is placed in a 12 gauge shotgun it will cause damage and serious injury. If 20 gauge shell is placed the it will slip pass the chamber and and when fired it will cause ersonal damage.

Explanation:

If 20 gauge shell is placed in a 12 gauge shotgun it will cause damage and serious injury. If 20 gauge shell is placed the it will slip pass the chamber and and when fired it will cause ersonal damage. So to avoid the damage you will have to see what gauge is written on the shell and check if it is same as on gun barrel. Be careful in choice of ammunition.

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Acceleration question plz help
andrezito [222]
For #5 It's helpful to draw a free body diagram so you know which way the forces are acting on the block.

the weight mg is acting downwards, and you need to find the vertical and horizontal components of mg using sin and cosine. so do 15x9.8xsin40 which is the force. Assuming no friction, this is the only force acting on the block, as the forces on the vertical plane cancel out i.e the normal force and weight of the block.

after, just do F=ma And since you know F and m, solve for a.
3 0
3 years ago
When operated on a household 110.0 V line, typical hair dryers draw about 1450 W of power. The current can be modeled as a long,
dezoksy [38]

Answer:

0.075A

Explanation:

We can consider this system as a circuit, hence we can take the current from the formula for the electric power as follow

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I hope this is useful for you

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4 0
3 years ago
What would happen to the coil if the current passing through it was too large?
Alborosie
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5 0
3 years ago
A force is applied to an object at rest with a mass of 100 kg. A force twice as large is applied to another object at rest with
MAVERICK [17]
The second object, the one that had twice the force applied to it, would move twice as far, I believe.
3 0
2 years ago
A firecracker in a coconut blows the coconut into three pieces. two pieces of equal mass fly off south and west, perpendicular t
kirill [66]

As per momentum conservation theory

If net force on a system is zero then initial momentum of the system will be equal to final momentum of that system.

Since initially coconut is at rest so initial momentum is zero

Here it break into three pieces such that two parts of same mass while third part is of double mass

now we can say

P_1 + P_2 + P_3 = 0

here we know that two parts fly off with same speed v0 along south and west directions

mv_0 (-\hat j) + mv_0 (-\hat i) + 2m \vec v = 0

now we will have

\vec v = \frac{v_0}{2}\hat i + \frac{v_0}{2}\hat j

so here magnitude of the speed of the third part will be

|v| = \sqrt{(\frac{v_0}{2})^2+(\frac{v_0}{2})^2}

|v| = \frac{v_0}{\sqrt2}

and the direction of the third part will be along North East direction

7 0
3 years ago
Read 2 more answers
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