An old penny rusting, remember you can’t undo a chemical change
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Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.
Elements form bonds to increase their stability. The main types of bonds are:
- Metallic bonds: they are formed between metals and the electrons are in a delocalized cloud.
- Ionic bonds: they are formed between metals (lose electrons) and nonmetals (gain electrons)
- Covalent bonds: they are formed between nonmetals, which share electrons.
Regarding the bonds in FesO₄:
- Fe is a metal and S a nonmetal, thus they will form ionic bonds.
- S and O are both nonmetals, thus they will form covalent bonds.
Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.
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B. The partial pressure of N2 is 101 kPa
<h3>Further explanation</h3>
Given
volume = 22.4 L
1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C
Required
Total pressure and partial pressure
Solution
Ideal gas law :
PV = nRT
n total = 3 mol
T = O °C + 273 = 273 K
P = nRT/V
P = 3 x 0.08205 x 273 / 22.4
P total = 3 atm = 303,975 kPa
P Nitrogen = 1/3 x 303.975 = 101.325 kPa
P Hydrogen = 2/3 x 303.975 = 202.65 kPa
The percentage error is given by multiplying relative error by 100%.
Therefore, to get the percentage error we need relative error which is given by dividing the absolute error with the actual value.
Absolute error = 0.133
Percentage error = 0.133/5.586 × 100%
= 2.38%
The percentage error is therefore; 2.38%
Explanation:
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