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Law Incorporation [45]
3 years ago
10

What elements are highlighted: a. Nonmetals b. Metals C. Metalloids

Chemistry
1 answer:
Advocard [28]3 years ago
6 0
Non metals
(It’s both halogens and noble gases ) the other ones which are white(not highlighted) are alkali metals, alkaline earth metals, and transition metals :3
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Which of the following is true for the theoretical yield of a reaction? (1 point)
just olya [345]

Answer:

It is always twice the value of the actual yield.

Explanation:

3 0
2 years ago
When you have a free metal ion, how do the energies of these orbitals relate to one another (are they the same, different, etc.)
7nadin3 [17]

Answer:

The energy of the orbitals are the same

Explanation:

For a free metal ion, all the d-orbitals are of the same energy. The five d-orbitals are said to be five fold degenerate in the free metal ion. Hence all the d-orbitals will possess the same energy irrespective of which one is first filled.

In an octahedral or tetrahedral crystal field, the d-orbitals will loose their degeneracy and become different in energy based on their orientation towards the ligands.

4 0
3 years ago
How many atoms are there in 3 moles of Fe?
Harrizon [31]
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6 0
3 years ago
What are heterogeneous and homogeneous?
vichka [17]
A homogeneous mixture has the same uniform appearance and composition throughout.
A heterogeneous mixture consists of visibly different substances or phases. The three phases or states of matter are gas, liquid, and solid.
A homogeneous mixture has the same uniform appearance and composition throughout. Many homogeneous mixtures are commonly referred to as solutions. A heterogeneous mixture consists of visibly different substances or phases.
3 0
2 years ago
2C4H10(g) +13O2(g) → 8CO2(g) +10H2O(g) Suppose a grill lighter contains 50.0 g of butane. How many grams of butane in the lighte
MatroZZZ [7]
Answer is: mass of butane is D)11.6 g.
m(butane) = 50,0 g.
V(CO₂) = 17,9 L.
n(CO₂) = V(CO₂) ÷ Vm.
n(CO₂) = 17,9 L ÷ 22,4 L/mol.
n(CO₂) = 0,8 mol.
From chemical reaction n(CO₂) : n(C₄H₁₀) = 8 : 2.
n(C₄H₁₀) = 0,8 mol ÷ 4.
n(C₄H₁₀) = 0,2 mol.
m(C₄H₁₀) = n(C₄H₁₀) · M(C₄H₁₀).
m(C₄H₁₀) = 0,2 mol · 58 g/mol.
m(C₄H₁₀) = 11,6 g.
8 0
3 years ago
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