Calculate the percent composition by mass of oxygen in litharge (gram formula mss=223.2 grams per mole)
2 answers:
Litharge is a yellow oxide of lead with a formula of PbO, which is formed by heating lead metal in air. The mass of one mole of PbO is 223.2 grams 1 mole of PbO contains 16 g of oxygen Therefore; the percentage of oxygen will be; (16/223.2) × 100 = 7.168 %
The % composition by mass of oxygen in litharge ( grams formula mass=223.2 g/mol) is calculated as below % composition is percentage by mass of each element in a compound which is calculated as follows %composition = molar mass of element/molar mass of compound x100 The molar mass of oxygen = 16 g/mol therefore the % composition = 16 g/mol/ 223.2 g/ mol x100 = 7.17 % of oxygen
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6 F2------->4 AlF3
F2-----------> 4/6 AlF3
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so 5.5 moles
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