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Artemon [7]
3 years ago
6

Calculate the percent composition by mass of oxygen in litharge (gram formula mss=223.2 grams per mole)

Chemistry
2 answers:
galben [10]3 years ago
4 0
Litharge is a yellow oxide of lead with a formula of PbO, which is formed by heating lead metal in air. 
The mass of one mole of PbO is 223.2 grams
1 mole of PbO contains 16 g of oxygen
Therefore; the percentage of oxygen will be;
     (16/223.2) × 100 = 7.168 %
kiruha [24]3 years ago
3 0
The  %  composition  by mass  of oxygen in litharge ( grams formula mass=223.2 g/mol) is  calculated as  below

%  composition is   percentage  by mass  of  each   element  in a  compound
which  is  calculated  as follows

%composition = molar mass  of element/molar  mass  of  compound  x100

The  molar mass of oxygen = 16 g/mol

therefore the % composition  = 16 g/mol/ 223.2 g/ mol  x100 = 7.17 %  of oxygen
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(2) pH = 13.35

(3) The given solution is not a buffer.

Explanation :

<u>(1) 53.1 mM HCl</u>

Concentration of HCl = 53.1mM=53.1\times 10^{-3}M

As HCl is a strong acid. So, it dissociates completely to give hydrogen ion and chloride ion.

So, Concentration of hydrogen ion= 53.1\times 10^{-3}M

pH : It is defined as the negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

pH=-\log (53.1\times 10^{-3})

pH=1.27

<u>(2) 0.223 M KOH</u>

Concentration of KOH = 0.223 M

As KOH is a strong base. So, it dissociates completely to give hydroxide ion and potassium ion.

So, Concentration of hydroxide ion= 0.223 M

Now we have to calculate the pOH.

pOH=-\log [OH^-]

pOH=-\log (0.223)

pOH=0.65

Now we have to calculate the pH.

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-0.65=13.35

<u>(3) 53.1 mM HCl + 0.223 M KOH</u>

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It is not a buffer because HCl is a strong acid and KOH is a strong base. Both dissociates completely.

As we know that the pH of strong acid and strong base solution is always 7.

So, the given solution is not a buffer.

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