Question

While excavating the tomb of Tutankhamen (d. 1325 BC), archeologists found a sling made of linen. The sling could hold a stone in a pouch, which could then be whirled in a horizontal circle. The stone could then be thrown for hunting or used in battle. Imagine the sling held a 0.10-kg stone; and it was whirled at a radius of 1.5 m with an angular speed of 2.0 rev/s. What was the angular momentum of the stone under these circumstances

Answer 1

Answer:

L = 2.83 J.s

Explanation:

The formula for the angular momentum of the stone is given as follows:

L = mvr

where,

L = angular momentum of the stone  = ?

m = mass of the stone = 0.1 kg

v = linear velocity of the stone = rω

r = radius of circular path = 1.5 m

ω = angular speed of the stone = (2 rev/s)(2π rad/1 rev) = 4π rad/s

Therefore,

L = mvr = m(rω)r

L = mr²ω

using values, we get:

L = (0.1 kg)(1.5 m)²(4π rad/s)

L = 2.83 J.s