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Vlad1618 [11]
3 years ago
10

While excavating the tomb of Tutankhamen (d. 1325 BC), archeologists found a sling made of linen. The sling could hold a stone i

n a pouch, which could then be whirled in a horizontal circle. The stone could then be thrown for hunting or used in battle. Imagine the sling held a 0.10-kg stone; and it was whirled at a radius of 1.5 m with an angular speed of 2.0 rev/s. What was the angular momentum of the stone under these circumstances
Physics
1 answer:
AleksAgata [21]3 years ago
4 0

Answer:

L = 2.83 J.s

Explanation:

The formula for the angular momentum of the stone is given as follows:

L = mvr

where,

L = angular momentum of the stone  = ?

m = mass of the stone = 0.1 kg

v = linear velocity of the stone = rω

r = radius of circular path = 1.5 m

ω = angular speed of the stone = (2 rev/s)(2π rad/1 rev) = 4π rad/s

Therefore,

L = mvr = m(rω)r

L = mr²ω

using values, we get:

L = (0.1 kg)(1.5 m)²(4π rad/s)

<u>L = 2.83 J.s</u>

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Answer:

The kinetic energy is: 50[J]

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E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\

In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.

When the elevation is 5 [m], we have a potential energy of

P_{e} =m*g*h\\P_{e} =1.01*9.81*5\\\\P_{e} = 50 [J]\\

This energy is equal to the kinetic energy, therefore

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10,500 J of GPE, weight 539 N, how tall is the hill you are sitting on?
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19.48 m

Explanation:

Gravitational potential energy = mgh

Current weight = 539 N

Weight = mg = 539 N

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Mass x 9.81 = 539

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6 0
3 years ago
A horizontal rectangular surface has dimensions 2.80 cm by 3.20 cm and is in a uniform magnetic field that is directed at an ang
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Answer:

magnitude of the magnetic field 0.692 T

Explanation:

given data

rectangular dimensions = 2.80 cm by 3.20 cm

angle of 30.0°

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solution

we take here rectangular side a and b as a = 2.80 cm and b = 3.20 cm

and here angle between magnitude field and area will be ∅ = 90 - 30

∅ = 60°

and flux  is express as

flux Ф = \int \vec{B}.d\vec{A}   .................1

and Ф = BA cos∅    ............2

so B = \frac{\phi }{Acos\theta }    

and we know

A = ab

so

B = \frac{\phi }{abcos\theta }    ..............3

put here value

B =  \frac{3.10\times 10^{-4} }{2.80 \times 10^{-2}\times 3.20 \times 10^{-2}\times cos60}  

solve we get

B = 0.692 T

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