Answer:
![EMF = 33880 Volts](https://tex.z-dn.net/?f=EMF%20%3D%2033880%20Volts)
Explanation:
As per Faraday's law of Electromagnetic induction we know that
Rate of change in magnetic flux will induce EMF in the closed conducting loop
so we have
![\phi = B.A](https://tex.z-dn.net/?f=%5Cphi%20%3D%20B.A)
now we have
![A = (110 \times 10^3)(110 \times 10^3)](https://tex.z-dn.net/?f=A%20%3D%20%28110%20%5Ctimes%2010%5E3%29%28110%20%5Ctimes%2010%5E3%29)
![A = 1.21 \times 10^{10}](https://tex.z-dn.net/?f=A%20%3D%201.21%20%5Ctimes%2010%5E%7B10%7D)
now we have
![\phi = B(1.21 \times 10^{10})](https://tex.z-dn.net/?f=%5Cphi%20%3D%20B%281.21%20%5Ctimes%2010%5E%7B10%7D%29)
now the induced EMF through this loop is given as
![EMF = (\frac{dB}{dt})(1.21 \times 10^{10})](https://tex.z-dn.net/?f=EMF%20%3D%20%28%5Cfrac%7BdB%7D%7Bdt%7D%29%281.21%20%5Ctimes%2010%5E%7B10%7D%29)
![EMF = (2.8 \times 10^{-6})(1.21 \times 10^{10})](https://tex.z-dn.net/?f=EMF%20%3D%20%282.8%20%5Ctimes%2010%5E%7B-6%7D%29%281.21%20%5Ctimes%2010%5E%7B10%7D%29)
![EMF = 33880 Volts](https://tex.z-dn.net/?f=EMF%20%3D%2033880%20Volts)
The change in the kinetic energy refers to the work done in displacing a body, thus, the change in the kinetic energy of an object refers to the work done on the object.
The correct formula to use is:
W = Initial kinetic energy - Final kinetic energy;
Where, W = change in kinetic energy
Final kinetic energy and initial kinetic energy = 1/2 MV^2
Initial velocity = 15 m/s
Final velocity = 13.5 m/s
Initial mass = 0.650 kg
Final mass = 0.950 kg
W = 1/2 [0.650* (15 *15)] - 1/2 [0.950 * (13.5 * 13.5)]
W = 146.25 - 173.13 = 26.88
Therefore, the change in kinetic energy is 26.88 J.
The negative sign has to be ignored, because change in kinetic energy can not be negative.
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M= ?
g=9.8 m/s (2)
h=20 m
Eg=362,600 J
Eg/mg
362,600 J/9.8 m/s (2) x 20 m
=1,850 m
Answer: it will travle 25km pr hour
Explanation:
sevide both by 2
Answer: 2.2x10^4
Explanation: in a adiabatic process pV^y = constant.
So V2=3V1 and p2 = p1 / 3^1.67 = 2.2x10^4 Pa