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abruzzese [7]
3 years ago
5

Find the voltage drop (in volt) along a 93.4 meter long 10 gauge copper wire carrying acurrent of 72.5 A. The diameter of a 10 g

auge wire is 2.5882 millimeters.
Physics
1 answer:
Sophie [7]3 years ago
3 0

Answer: 5.41 V

Explanation:in order to explain this result we have to use the Ohm law given by:

ΔV=R*I where R is the resistance which is equal R= ρ*L/A . ρ is the resistivity, L the length of the wire and A is the cross section. I is the current.

Then we have

ΔV=ρ*L*I/A= 1.68 * 10^-8 Ωm*93.4 m*72.5A/2.1* 10^-5 m^2=5.41 V

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Answer:

E=8*10^5\frac{V}{m}

Explanation:

The magnitude of the electric field between two parallel conducting plates is defined as:

E=\frac{\Delta V}{d}

Here \Delta V is the potential difference between the plates and d its separation.

The electric potential energy is defined as the product between the particle's charge and the potential difference:

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Solving for \Delta V and replacing in the electric field formula:

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In this case we have a double charged ion, so q=2e:

E=\frac{32*10^3eV}{(2e)(2*10^{-2}m)}\\E=8*10^5\frac{V}{m}

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24 miles

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