Polar Easterlies: From 60-90 degrees latitude.
Prevailing Westerlies: From 30-60 degrees latitude (aka Westerlies).
Tropical Easterlies: From 0-30 degrees latitude (aka Trade Winds).
The volume of the balloon is given by:
V = 4πr³/3
V = volume, r = radius
Differentiate both sides with respect to time t:
dV/dt = 4πr²(dr/dt)
Isolate dr/dt:
dr/dt = (dV/dt)/(4πr²)
Given values:
dV/dt = 72ft³/min
r = 3ft
Plug in and solve for dr/dt:
dr/dt = 72/(4π(3)²)
dr/dt = 0.64ft/min
The radius is increasing at a rate of 0.64ft/min
The surface area of the balloon is given by:
A = 4πr²
A = surface area, r = radius
Differentiate both sides with respect to time t:
dA/dt = 8πr(dr/dt)
Given values:
r = 3ft
dr/dt = 0.64ft/min
Plug in and solve for dA/dt:
dA/dt = 8π(3)(0.64)
dA/dt = 48.25ft²/min
The surface area is changing at a rate of 48.25ft²/min
Answer:
Incomplete question: "A signal of 20.7 mV is measured at a distance of 29 mm and 15.8 mV is measured at 32.5 mm. Correct the data for background and normalize the data to the maximum value. What is the normalized corrected value at 32.5 mm?"
The normalized corrected value at 32.5 mm is 0.1638
Explanation:
The corrected light measurement at 29 mm is equal to:
20.7 - 5.1 = 15.6 mV
The corrected light measurement at 32.5 mm is equal to:
15.6 - 5.1 = 10.5 mV
To normalize the data to its maximum value means that the maximum value must be calculated and the data must be scaled using that value, as in this case the maximum value is 15.6 mm, then the normalized corrected value at 32.5 mm is equal to:
10.5 * 15.6 = 163.8 = 0.1638
Answer:
A) That man-made trade barriers are the biggest challenge facing Africa's international trade success.
Explanation:
Based on the discussion of high trade costs, the presence of numerous tariffs, and problems with customs procedures and duties it is clear that the author feels that man-made trade barriers are the biggest challenge facing Africa's international trade success.
Answer:
17.5 m
Explanation:
First of all, we need to find the time the arrow need to cover the horizontal distance between the starting point and the orange, which is
x = 49.0 m
We start by calculating the horizontal component of the arrow's velocity:
And this horizontal velocity is constant during the entire motion. So, the time taken to reach the horizontal position of the orange is
Now we can find the height of the arrow at that time by using the equation for the vertical position:
where:
h = 1.30 m is the initial height
is the initial vertical velocity
t = 1.57 s is the time
is the acceleration of gravity
Substituting into the equation, we find
