Two forces P and Q act on an object.<br>Which diagram shows the resultant of these two forces?

Electricity costs 10p per unit. How much will it cost Sam to use a 85W laptop and a 60W lamp for an hour?

Goryan [66]

The standard unit is KW/hr, = 1,000W/hr.
(85 + 60) = 145W.
You need to find its fraction of 1,000W., so (145/1000) = 0.145 KWH.
(0.145 x 10p) = 1.45p. per hr.

6 0

2 years ago

A number is written in scientific notation when it is the product of a number less than 10 but greater than or equal to 1 and a

Bess [88]

Answer:

$Mass = 1.99 * 10^{30} kg$

Explanation:

Given

$Mass = 1,990,000,000,000,000,000,000,000,000,000\ kg$

Required

Rewrite using scientific notation

The format of a number in scientific notation is

$Digit = a * 10^n$

Where $1 \geq\ a\geq\ 10$

So the given parameter can be rewritten as

$Mass = 1.99 * 1,000,000,000,000,000,000,000,000,000,000\ kg$

Express as a power of 10

$Mass = 1.99 * 10^{30} kg$

Hence, the equivalent of the mass of the sun in scientific notation is:

$Mass = 1.99 * 10^{30} kg$

7 0

3 years ago

Based on Kepler's work, which best describes the orbit If a planet around the Sun?

krek1111 [17]

Answer:

an ellipse with the Sun at one focus or D

Explanation:

Answer for edgenuity

7 0

3 years ago

List five situations in which a lesser amount of friction would be beneficial. Overall, would a high or low coefficient of frict

Natalka [10]

Low coefficient of friction

1. flying a plane (friction between air and plane)
2. ice skating (friction between ice and skate blade)
3. swimming (water & skin)
4. rowing a boat (water and boat)

6 0

3 years ago

Read 2 more answers

The net horizontal force on a car is 981 N. The car has a mass of 1550 kg and the force is applied when the car has a speed of 2

viktelen [127]

Answer:

Distance, d = 778.05 m

Explanation:

Given that,

Force acting on the car, F = 981 N

Mass of the car, m = 1550 kg

Initial speed of the car, v = 25 mi/h = 11.17 m/s

We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:

$F=ma\\\\a=\dfrac{F}{m}\\\\a=\dfrac{981}{1550}\\\\a=0.632\ m/s^2$

Let d is the distance covered by car. Using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2\\\\d=11.17\times 35+\dfrac{1}{2}\times 0.632\times (35)^2\\\\d=778.05\ m$

So, the car will cover a distance of 778.05 meters.

5 0

3 years ago

Two forces P and Q act on an object.Which diagram shows the resultant of these two forces?​

Two forces P and Q act on an object.Which diagram shows the resultant of these two forces?