Answer:
Frequency of photon is 0.513×10¹⁵ s⁻¹
Explanation:
Given data:
Energy of photon = 3.4×10⁻¹⁹ J
Frequency of photon = ?
Planck's constant = 6.63 × 10⁻³⁴ Js
Solution:
Formula:
E = hf
3.4×10⁻¹⁹ J = 6.626 × 10⁻³⁴ Js × f
f = 3.4×10⁻¹⁹ J / 6.626 × 10⁻³⁴ Js
F = 0.513×10¹⁵ s⁻¹
Frequency of photon is 0.513×10¹⁵ s⁻¹.
The mass of the ethylene glycol used is 14.26 g
<h3>What is the freezing point?</h3>
The freezing point is the temperature at which a liquid is converted to a solid.
Given that;
ΔT = 0.0°C - ( -4.3°C) = 4.3°C
ΔT = 4.3°C
But we know that
ΔT = k m i
m = ΔT/k i
m = 4.3°C/1.86 °C/m * 1
m = 2.3 m
Now;
Let the mass of ethylene glycol be m
Molar mass of ethylene glycol = 62 g/mol
Mass of solvent = 100.0 g or 0.1 Kg
Then;
2.3= m/62/0.1
2.3 = m/62 * 0.1
m = 2.3 * 62 * 0.1
m = 14.26 g
Learn more about freezing point:brainly.com/question/3121416?
#SPJ1
<span>D. It shows that the electrons within an atom do not have sharp boundaries.</span>
<h3><u>Answer;</u></h3>
The temperatures of the two substances equalize.
<h3><u>Explanation</u>;</h3>
- When two objects at different temperatures are placed in contact, heat flows from the warmer object to the cooler one until the temperature of both objects is the same.
- <u>The amount of heat that flows from a warmer object is the same as the amount of heat that flows into a cooler object. Because the direction of heat flow is opposite for the two objects, the sign of the heat flow values must be opposite.</u>
- In line with the law of conservation of energy, the amount of heat lost by a warmer object equals the amount of heat gained by a cooler object. Therefore the amount of heat lost by carbon dioxide is equal to the amount of heat gained by water.