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olga2289 [7]
3 years ago
8

GIVE ME BRAINLIEST!!!! nah im jk lol ANYWAY HAVE A GREAT DAY!

Chemistry
1 answer:
topjm [15]3 years ago
5 0

Answer:

okie then you too

                     

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A research team has just discovered a new element called Likhitium. Now they need to determine the average atomic mass in order
earnstyle [38]

The question is incomplete, the complete question is shown in the image attached to this answer.

Answer:

139.13

Explanation:

The average atomic mass of the element Likhitium is the sum of the relative abundance of all the isotopes of Likhitium.

We obtain the relative atomic mass of Likhitium as follows;

(44.7/100 * 138) + (52.3/100 * 139) + (0.5/100 * 140) + (2.5/100 * 141)

61.7 + 73.2 + 0.7 + 3.53 = 139.13

Hence the relative abundance of Likhitium is 139.13

6 0
3 years ago
A chemist plans to use 435.0 grams of ammonium nitrate ion a reaction. How many moles of the compound is this?
AURORKA [14]
Ammonium Nitrate has the formula NH4NO3, and has a formula weight of 80.043 grams/mole. We can convert the amount in the problem to moles using this conversion factor. Divide 435 by 80.043 to find the number of moles.

435/80.043 = 5.435

This amount of Ammonium Nitrate contains 5.44 moles of substance, adjusted for significant figures.
4 0
3 years ago
How do you identify unknown chemicals.
QveST [7]

Answer:

Preventing Unknown Chemicals

Label all chemical containers, including beakers, flasks, vials, and test tubes.

Immediately replace labels that have fallen off or that are deteriorated.

Label containers using chemical names. ...

Archived research samples are often stored in boxes containing hundreds of small vials.

7 0
3 years ago
A solid and a liquid are shaken together in a test tube to produce a milky mixture that eventually separates into a clear liquid
mrs_skeptik [129]
This is called suspension
8 0
4 years ago
What is the value of 1.5 ATM of gas at 20°C and a 3 L vessel are heated at 30°C at a pressure of 5.2 ATM
vampirchik [111]

Answer:

The answer will be approximately 1.0L

Explanation:

The problem has not been properly specified. You could have specified a gas in a PISTON, whose volume would decrease with increased pressure, and increase with increased temperature.

For such a system, we would use the  

combined gas law:

\frac{P1V1}{T1}=\frac{P2V2}{T2}

V_{2}= \frac{P1V1}{T1}\times\frac{T2}{P2}

                       =\frac{1.5\times3.0\times303}{293\times5.2}

                        \approx1.0L

6 0
3 years ago
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