solution:
the given compounds are sodium acetate, 1M HCL,NaHCO₃ and Na2CO₃
pH of the buffer solution is 4.7
the value of pKa of sodium bicarbonate is 6.37
the value of pKa of acetic acid is 4.7
calculate concentration of acetic acid by using the following forumula
pH=pKa+lag[salt]/[acid]
substitute the pH and Pka values in the formula.
4.7=4.7+log[salt]/[acid]
log[salt]/[acid]=0
thus, the concentration ratio of the salt and acid should be equal to each other.
Thus, concentration of sodium acetate is 0.05M
Concentration of sodium acetate= concentration of acid
= 0.05M
Volume of the buffer solution is 100mL
The buffer solution can be prepared as 0.05M of 50mL sodium acetate will react with 0.05M of 50mL of 0.05M of HCL.
The chemical equation for neutralization of the weak base with strong can be represented as show as
CH₃COONa+HCL-->CH₃COOH+NaCL
Answer:
I think that it is A I am sorry if I am wrong
Explanation:
What part is the independent variable and what part is the dependent variable of the seminary the blood pressure of a soldier is measured while he’s resting soldiers and exposed to a stressful environment and his blood pressure is measured in
Answer:
84.8 mL
Explanation:
From the question given above, the following data were obtained:
Mass of CuNO₃ = 3.53 g
Molarity of CuNO₃ = 0.330 M
Volume of solution =?
Next, we shall determine the number of mole in 3.53 g of CuNO₃. This can be obtained as follow:
Mass of CuNO₃ = 3.53 g
Molar mass of CuNO₃ = 63.5 + 14 + (16×3)
= 63.5 + 14 + 48
= 125.5 g/mol
Mole of CuNO₃ =?
Mole = mass / Molar mass
Mole of CuNO₃ = 3.53 / 125.5
Mole of CuNO₃ = 0.028 moles
Next, we shall determine the volume of the solution. This can be obtained as follow:
Molarity of CuNO₃ = 0.330 M
Mole of CuNO₃ = 0.028 moles
Volume of solution =?
Molarity = mole /Volume
0.330 = 0.028 / Volume
Cross multiply
0.330 × Volume = 0.028
Divide both side by 0.330
Volume = 0.028 / 0.330
Volume = 0.0848 L
Finally, we shall convert 0.0848 L to millilitres (mL). This can be obtained as follow:
1 L = 1000 mL
Therefore,
0.0848 L = 0.0848 L × 1000 mL / 1 L
0.0848 L = 84.8 mL
Therefore, the volume of the solution is 84.8 mL.
While the number nuclear protons as given is 34, and therefore we deal with the element selenium, there are 2 more electrons than protons, and therefore this species has an overall
2
−
charge.
We represent this selenide ion as
S
e
2
−
. Do I win 5 pounds?
Z= 34, therefore the atom is selenium
