Mystical ride her scooter down the hill from the state of rest when she reaches the bottom of the hill 4.0 seconds later her spe
1 answer:
The acceleration is
Explanation:
This is a uniformly accelerated motion (constant acceleration), therefore we can apply the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the scooter in this problem, we have
u = 0 (it starts from rest)
v = 10.0 m/s is the final velocity
t = 4.0 s is the time interval
Solving for a, we find the acceleration:
Learn more about acceleration:
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Answer:
When a number is written in scientific notation (representing the number using powers of base ten) it is expressed so that it contains a digit in the place of the units and all other digits after the decimal point, multiplied by the respective exponent. For example, the number .
On the other hand, it is known the units in the SI for mass, length, time and temperature are kilogram (kg), meter (m), second (s) and Kelvin (K), respectively. In addition, thera are prefixes of the International System (SI) that indicate a specific factor of 10.
For example:
-Giga (G) is a prefix that indicates a factor of
-Pico (p) is a prefix that indicates a factor of
-Mili (m) is a prefix that indicates a factor of
-Micro () is a prefix that indicates a factor of
-Tera (T) is a prefix that indicates a factor of
-Kilo (K) is a prefix that indicates a factor of
Knowing this, let's express these quantities in terms of the SI base units:
Answer:
Part a: The eccentricity is 1.086.
Part b: The altitude at closest approach is 5088 km
Part c: The velocity at perigee is 8.516 km/s
Part d: The turn angle is 134.08 while the aiming radius is 5641.28 km
Explanation:
<h2>Part a </h2>Specific energy is given by
Here
- ε is the specific energy
- v is the velocity which is given as 2.23 km/s
- μ is the gravitational constant whose value is 398600
- r is the distance between earth and the meteorite which is 402,000 km
Value of specific energy is also given as
Orbit formula is given as
Putting values in this equation and solving for e via the quadratic formula gives
As the value of eccentricity cannot be negative so the eccentricity is 1.086.
<h2>Part b</h2>The radius of trajectory at perigee is given as
Substituting values gives
Now for estimation of altitude z above earth is given as
So the altitude at closest approach is 5088 km
<h2>Part c</h2>radius of perigee is also given as
Rearranging this equation gives
Now the velocity at perigee is given as
So the velocity at perigee is 8.516 km/s
<h2>Part d</h2>Turn angle is given as
Substituting value in the equation gives
Aiming radius is given as
Substituting value in the equation gives
So the turn angle is 134.08 while the aiming radius is 5641.28 km