A 600 kg car is at rest, and then accelerates to 5 m/s.
1 answer:
Answer:
0
7500J
7500J
Explanation:
Given parameters:
Mass of car = 600kg
Velocity = 5m/s
Unknown:
Original kinetic energy = ?
Final kinetic energy = ?
Work used = ?
Solution:
The kinetic energy of a body is the energy due to the motion of a body.
It can be solve mathematically using expression below;
K.E = m v²
where m is mass
v is velocity
original kinetic energy;
The car started at rest and v = 0, therefore K.E = 0
Final kinetic energy;
K.E = x 600 x 5² = 7500J
Work done:
Work done = Final K.E - Initial K.E = 7500 - 0 = 7500J
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Answer:
Displacement: 6.71 m, Direction: 63.4 degrees north of east
Explanation:
In the attached image we can aprecciate each one of the movements of the parade. Let's say that the parade started from the origin (point (0,0)) then it moves to the east 4 blocks it means now the parade is located at point (4,0).
Then the parade went to the south three blocks, so it moves to the coordinate (4,-3). After this the parade went to the west one block so the new coordinate point is (3, -3).
And finally the movement of the 0 parade was 9 blocks to the north. It means the final point is now (0,9) - (3,-3) = (3,6)
And the displacement will be defined by the folliwing vector operation:
We know that the magnitude of the displacement vector is defined by the phytagoras theorem
And the angle will be defined by:
tan(beta)=3/6
beta = tan^-1(6/3)
beta = 63.43°
