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Stels [109]
3 years ago
9

What is the maximum number of electrons that can be contained in the first, second, third, and fourth energy levels, respectivel

y?
Chemistry
1 answer:
Natalija [7]3 years ago
6 0
It can be determined by 2n^2 formula 
where "n" is the no of shell:
1st shell = 2n^2 = 2(1)^2 = 2*1 = 2 electrons
2nd shell = 2n^2 = 2(2)^2 = 2*4 = 8 electrons
3rd shell = 2n^2 = 2(3)^2 = 2*9 = 18 electrons
4th shell = 2n^2 = 2(4)^2 = 2*16 = 32 electrons.
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Answer:

Esters are both inorganic and organic acids .... Regarding the second question, it is believed that it is carried out in this way in order to recognize the C-terminal amino acid in a peptide within a protein

Explanation:

The explanation of this question is according to what was interpreted in the question, since it is considered that it is poorly written ...

What happens in this chemical reaction is that it first becomes an ester (organic or inorganic acid) so that it is later recognized in the complex peptide structure.

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We employ the osmotic pressure equation to determine the solute's concentration, which is:

π = iMRT

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7 0
1 year ago
If you have a 150-gram sample of CrO3: • How many moles of CrO3 do you have? • How many oxygen atoms do you have? • How many gra
docker41 [41]

Answer :

(a) The moles of CrO_3 is, 1.5 moles.

(b) The number of oxygen atoms are, 27.099\times 10^{23}

(c) The mass of oxygen is, 72 grams.

Explanation : Given,

Mass of CrO_3 = 150 g

Molar mass of CrO_3 = 100 g/mole

Molar mass of oxygen = 16 g/mole

(a) First we have to calculate the moles of CrO_3.

\text{Moles of }CrO_3=\frac{\text{Mass of }CrO_3}{\text{Molar mass of }CrO_3}=\frac{150g}{100g/mole}=1.5moles

The moles of CrO_3 is, 1.5 moles.

(b) Now we have to calculate the number of oxygen atoms.

In CrO_3, there are 1 atom of chromium and 3 atoms of oxygen.

According to the mole concept,

1 mole of CrO_3 contains 3\times 6.022\times 10^{23} number of oxygen atoms.

So, 1.5 mole of CrO_3 contains 1.5\times 3\times 6.022\times 10^{23}=27.099\times 10^{23} number of oxygen atoms.

The number of oxygen atoms are, 27.099\times 10^{23}

(c) Now we have to calculate the mass of oxygen.

As, 1 mole of CrO_3 contains 3 moles of oxygen

So, 1.5 mole of CrO_3 contains 1.5\times 3=4.5 moles of oxygen

\text{Mass of oxygen}=\text{Moles of oxygen}\times \text{Molar mass of oxygen}

\text{Mass of oxygen}=(4.5mole)\times (16g/mole)=72g

The mass of oxygen is, 72 grams.

3 0
3 years ago
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