Question

A low C (f=65Hz) is sounded on a piano. If the length of the piano wire is 2.0 m and

Answer 1

Answer:

T = 676 N

Explanation:

Given that: f = 65 Hz, L = 2.0 m, and ρ = 5.0 g$/m^{2}$ = 0.005 kg

A stationary wave that is set up in the string has a frequency of;

f = $\frac{1}{2L}$$\sqrt{\frac{T}{M} }$

⇒      T = 4$L^{2}$$f^{2}$M

Where: t is the tension in the wire, L is the length of the wire, f is the frequency of the waves produced by the wire and M is the mass per unit length of the wire.

But M = L × ρ = (2 × 0.005) = 0.01 kg/m

T = 4 × $2^{2}$ ×$65^{2}$ × 0.01

   = 4 × 4 ×4225 × 0.01

   = 676 N

Tension of the wire is 676 N.