One is the best choice for an answer.
A and C
Imagine u are shooting a laser pointer at a mirror this is pretty much what it is
v₀ = initial velocity of the mobile = 10 m/s
v = final velocity of the mobile = 20 m/s
a = acceleration of the mobile = 5 m/s²
d = distance traveled during this operation = ?
Using the kinematics equation
v² = v²₀ + 2 a d
inserting the above values in the equation
20² = 10² + 2 (5) d
400 = 100 + 10 d
subtracting 100 both side
400 - 100 = 100 - 100 + 10 d
300 = 10 d
dividing both side by 10
300/10 = 10 d/10
d = 30 m
hence mobile travels 30 m.
Answer: 5.30m
Explanation:
depth of pool = 3.2 m
i = 67.75°
Using snell's law, we have,
n₁ × sin(i) = n₂ × 2 × sin(r)
n₁ = 1, n₂ =1.33, r= 44.09°
Hence,
Distance of Google from edge if pool is:
2.2 + d×tan(r) = 2.2 + (3.2 × tan(44.09°) =5.30m
Answer:
0.015m^3
Explanation:
1 m^3 = 1000 liters
x m^3 = 15 liters
Cross multiply
xm^3 x 1000 l = 15 l
Divide both sides by 1000
xm^3 x1000/1000 = 15/1000
xm^3 = 0.015m^3
Therefore 15 liter = 0.015m^3
