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tresset_1 [31]
3 years ago
15

If angle 2 measures 72°, what is the measure of angle 3?

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0

Answer:

angle 3 =108degree

Step-by-step explanation:

angle 2 + angle 3 is 180 degree. because they are the angles on the same line.

then subtract angle 2 from 180 and you will get 108 degree

You might be interested in
92​% of what number is 253​?
Romashka-Z-Leto [24]
Let, the number = x
Then, x * 92% = 253
x = 253 / 0.92   [ 92% = 0.92 ]
x = 275

In short, Your Answer would be 275

Hope this helps!
3 0
3 years ago
Which questions best describes: A tire manufacturer has a 60,000 mile warranty for tread life. The manufacturer considers the ov
seropon [69]

This question is incomplete because the answer choices were not provided. The complete question was obtained from google as:

A tire manufacturer has a 60,000 mile warranty for tread life. The manufacturer considers the overall tire quality to be acceptable if less than 5% are worn out at 60,000 miles. The manufacturer tests 250 tires that have been used for 60,000 miles. They find that 3.6% of them are worn out. With this data, we test the following hypotheses.

H0: The proportion of tires that are worn out after 60,000 miles is equal to 0.05.

Ha: The proportion of tires that are worn out after 60,000 miles is less than 0.05.

In order to assess the evidence, which question best describes what we need to determine?

a. If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be 3.6% or less?

b. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be 5%?

c. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be less than 5%?

d. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be 3.6%?

e. If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be less than 5%?

Answer:

Option A is the correct question - If we examine a sample of tires used for 60,000 miles and determine the proportion that is worn out, how likely is that proportion to be 3.6% or less?

Step-by-step explanation:

The correct question that describes what needs to be determined is expressed in option A as this will give us p-value and we will guide us in deciding whether to keep or reject the null hypothesis

Thus option A is the correct question - If we examine a sample of tires used for 60,000 miles and determine the proportion that is worn out, how likely is that proportion to be 3.6% or less?

7 0
3 years ago
Simplify y^2-6y-7/2y^2-17y+21
Elza [17]
The answer is y^2-23y+-7y^2/2+21
6 0
3 years ago
Can someone please please please help with this problem preferably by the end of today? (later is fine too tho)
V125BC [204]

Answer:

Add all of the items, then multiply by 5

Step-by-step explanation:

Why by 5? Well, in order to make

5 cookies per player one batch would be made

so, 10 cookies pp = 2 batches

15 cookies pp = 3 batches

20 cookies pp = 4 batches

and then you would need 4 more to make 2 dozen, so you would then make another batch and have a few extra, but you would have 2 dozen per player!

hope this helps!!

3 0
2 years ago
probability that cars have been assembled in a particular plant as follows: P(plant1)=20% , P(plant 2)=24% , P(plant 3.25% , P(p
Bogdan [553]

Answer:

16800/year

Step-by-step explanation:

Plant 1= 20%

Plant 2 = 24%

Plant 3 = 25%

Plant 4 = 31%

Total cars produced 100% = 1,200,000

Number of cars produced in plant 1 =

20% of 1,200,000 = 0.2 x 1,200,000 = 240,000 cars

Number of cars produced in plant 2 =

24% of 1,200,000 = 0.24 x 1,200,000 = 288,000 cars

Number of cars produced in plant 3 =

25% of 1,200,000 = 0.25 x 1,200,000 = 300,000 cars

Number of cars produced in plant 4 =

31% of 1,200,000 = 0.31 x 1,200,000 = 372,000 cars

Number of cars with no warranty claim in plant 1/year 223200

Number of cars with warranty claims in plant 1 + number of cars with no warranty claim in plant 1  = total number of cars produced in plant 1

X + 223200 = 240000  

X = 240000 - 223200

X = 16800/year

number of cars with warranty claim in plant 1/ year is 16800

6 0
3 years ago
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