A meterstick pivoted about a horizontal axis through the O-cm end is held in a horizontal position and let go. (a) \A{rat is the
1 answer:
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Answer:
9.6 m/s
Explanation:
Angle of projection, θ = 28°
Horizontal distance, R = 7.8 m
Let the velocity of projection is given by u.
The formula used to find the velocity of projection is given by
u = 9.6 m/s
Thus, the velocity of projection is 9.6 m/s.
Answer:
There are two possible solutions.
M1 = 4.68*10^30kg, M2 = 5.53*10^30kg
M1 = 5.53*10^30kg, M2 = 4.7*10^29kg
Explanation:
In order to find the mass of each black hole, you take into account the gravitational force between them and the sum of their masses.
You use the formula for the gravitational force between two masses:
(1)
G: Cavendish's constant = 6.674*10^-11 m^3/kg.s^2
M1, M2: mass of each black hole = ?
r: distance between the black holes = 10.0 AU = 10.0(1.50*10^11m) = 1.5*10^12m
Fg: gravitational force between the black holes = 7.70*10^25N
Furthermore, you take into account that the sum of the masses M1 and M2 is:
M1 + M2 = 6.00*10^30 kg (2)
You solve the equation (2) for M2.
Next, you replace the obtained expression for M2 into the equation (1) and solve for M1, as follow (for simplicity, you do not add the units):
Then, you have obtained a quadratic polynomial. You solve it with the quadratic formula:
Both results are consistent, then the mass of one black hole can be 4.68*10^30kg and also 5.53*10^30kg.
The other black hole has a mass of:
Hence, you have a pair of solutions:
M1 = 4.68*10^30kg, M2 = 5.53*10^30kg
M1 = 5.53*10^30kg, M2 = 4.7*10^29kg
Answer:
The amount of energy required is
Explanation:
The energy required to convert the ice to steam is the sum of:
1) Energy required to raise the temperature of the ice from -20 to 0 degree Celsius.
2) Latent heat required to convert the ice into water.
3) Energy required to raise the temperature of water from 0 degrees to 100 degrees
4) Latent heat required to convert the water at 100 degrees to steam.
The amount of energy required in each process is as under
1)
where
' is specific heat of ice =
2) Amount of heat required in phase 2 equals
3) The amount of heat required to raise the temperature of water from 0 to 100 degrees centigrade equals
where
' is specific heat of water=
4) Amount of heat required in phase 4 equals
Thus the total heat required equals