Question

Given: m∠ABC = m∠CBD Prove: Ray B C bisects ∠ABD. 3 lines extend from point B. One line extends to point A, another to C, and another to D. Justify each step in the flowchart proof. A flow chart with 3 boxes that are labeled A, B, C, from top to bottom. Box A contains m angle A B C = m angle C B D. Box B contains angle A B C is-congruent-to angle C B D. Box C contains Ray B C bisects angle A B D.

Answer 1

Answer:

Given that m∠ABC = m∠CBD, and m∠ABD = m∠ABC + m∠CBD BC bisects m∠ABD (Definition of angle bisector)

Step-by-step explanation:

The given information are;

m∠ABC = m∠CBD

To prove that Ray BC bisects m∠ABD

The description is therefore;

Three lines (AB, BC, and BD) that meet at a point

The content of Box A = m∠ABC = m∠CBD

The content of Box B = m∠ABC ≅ m∠CBD

The content of Box C = Ray BC bisects  m∠ABD

Therefore, we have;

m∠ABD = m∠ABC + m∠CBD (Angle addition postulate)

m∠ABC = m∠CBD (Given)

∴ m∠ABC ≅ m∠CBD (Definition of congruent angles)

m∠ABC is adjacent to m∠CBD (Description of the angles)

Line BC is common to m∠ABC and m∠CBD (Description of the angles)

Therefore, given that m∠ABC = m∠CBD, and m∠ABD = m∠ABC + m∠CBD BC bisects m∠ABD (Definition of angle bisector).