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stich3 [128]
3 years ago
13

Alice climbs 100 meters directly up the face of a cliff to reach the summit. Her friend Peter hikes the long way around taking a

3 km trail to meet her at the top of the cliff. Compare the distance and displacement of the two friends.
Physics
1 answer:
SOVA2 [1]3 years ago
4 0

Answer:

Alice Distance = 100 meters

Peter's Distance = 3 km

Alice Displacement and Peter's displacement are both 100 meters upwards.

Explanation:

To solve this question, we have to first define distance and displacement.

Distance is simply the measurement of the sum of all paths travelled from one point to another while displacement is measurement of the shortest distance from initial point to final point.

Now, Alice and Peter are moving from the same point.

Alice distance travelled is 100 meters.

Also, her displacement will be 100 meters because it is the shortest distance to the summit of the cliff.

Now, for Peter, he decides to take a longer route which is 3 km in distance.

However, the shortest path which is the displacement is still 100 meters.

Thus, Peter's displacement is 100 meters.

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You are working in a shoe test laboratory measuring the coefficients of friction for running shoes on a variety of surfaces. The
AnnZ [28]

Answer:

0.75

Explanation:

Since the static frictional force is the maximum force applied just before sliding, our frictional force, F is 300 N.

Since F = μN where μ = coefficient of static friction and N = normal force = 400 N (which is the downward force applied against the surface).

So, μ = F/N

= 300 N/400 N

= 3/4

= 0.75

So, the  coefficient of static friction μ = 0.75

6 0
2 years ago
12.51 A parallel RLC circuit, which is driven by a variable frequency 2-A current source, has the following values: R = 1 kΩ, L
Anastaziya [24]

Answer:

BW = 100 rad/s

wlow = 452.49 rad/s

whigh = 552.49 rad/s

V(jwlow) =1414.21 < 45°V

V(jwhigh) =1414.21 <-45°V

Explanation:

To calculate bandwidth we have formula

BW = 1/RC

BW = 1/ 1000x10x10^¯6

BW = 100 rad/s

We will first calculate resonant frequency and quality factor for half power frequencies.

For resonant frequency

wo = 1/(SQRT LC)

wo = 1/SQRT 400×10¯³ × 10×10^¯6

wo = 500 rad/s

For Quality

Q = wo / BW

Q = 500/100

Q = 5

wlow = wo [-1/2Q+ SQRT (1/2Q)² + 1]

wlow = 500 [-1/2×5 + SQRT (1/2×5)² + 1]

wlow = 452.49 rad/s

whigh = wo [1/2Q+ SQRT (1/2Q)² + 1]

whigh = 500 [1/2×5 + SQRT (1/2×5)² + 1]

whigh = 552.49 rad/s

We will start with admittance at lower half power frequency

Y(jwlow) = (1/R) + (1/jwlow L) + (jwlow C)

Y(jwlow) = (1/1000) + (1/j×452.49×400×10¯³) + (j×452.49×10×10^¯6)

Y(jwlow) = 0.001 - j5.525×10¯³ + j4.525×10¯³

Y(jwlow) = (1-j).10¯³ S

Voltage across the network is calculated by ohm's law

V(jwlow) = I/Y(jwlow)

V(jwlow) = 2/(1-j).10¯³

V(jwlow) = 1414.2 < 45°V

Now we will calculate the admittance at higher half power frequency

Y(jwhigh) = (1/R) + (1/jwhigh L) + (jwhigh C)

Y(jwhigh) = (1/1000) + (1/j×552.49×400×10¯³) + (j×552.49×10×10^¯6)

Y(jwhigh) = 0.001 - j4.525×10¯³ + j5.525×10¯³

Y(jwhigh) = (1+j).10¯³ S

Voltage across network will be calculated by ohm's law

V(jwhigh) = I/Y(jwhigh)

V(jwhigh) = 2/(1+j).10¯³

V(jwhigh) = 1414.2 < - 45°V

6 0
3 years ago
A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its maximum displacement from
Mrac [35]

Answer:

C) True. At maximum displacement, its instantaneous velocity is zero.

Explanation:

The simple harmonic movement is given by

        x = A cos wt

Speed

        v = - A w sin wt

At the point of maximum displacement x = A

       A = A cos wt

      cos wt = 1

      wt = 0

We replace the speed

       v = -Aw sin 0 = A w

Speed ​​is maximum

Let's review the claims

A) False. Speed ​​is zero

B) False. It can be determined

C) True. Agree with our result

D) False. When one is maximum the other is minimum

4 0
2 years ago
A boat moves with a speed of +2.5 m/s in a direction 25° north of east. If the mass of the boat is 15,000 kg, what is the moment
nadya68 [22]
Momentum - mass in motion
P=MV
P=(15,000 kg)(2.5 m/s)
P=37 500 kg x m/s to the north
Hope this helps
5 0
3 years ago
What is the current in a series circuit with a resistance of 30 ohms and a potential difference of 120 volts?
mars1129 [50]
0.25A....................
7 0
3 years ago
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