Question

what is the molar ratio between oxygen and carbon dioxide, given the following equation? 2C4H10 + 13O2 right arrow 8CO2 + 10H2O

Answer 1

2C4H10 + 13O2 -----------> 8CO2 + 10H2O

Number of moles 13 mole of O2 : 8 mole of CO2

Molar ratio: n(O2) :n(CO2) = 13 : 8

n is a number of moles.

Answer 2

Answer : The molar ratio between the oxygen and carbon dioxide is, 13 : 8

Explanation :

The given balanced chemical reaction is :

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

By the stoichiometry we conclude that, 2 moles of $C_4H_{10}$ react with 13 moles of $O_2$ to give 8 moles of $CO_2$ and 10 moles of $H_2O$ as a product.

That means,

The molar ratio between the $C_4H_{10}:O_2:CO_2:H_2O$ are $2:13:8:10$ respectively.

Thus, the molar ratio between the $O_2:CO_2$ is, $13:8$ respectively.