Answer:
C1V1=C2V2
C1 is 2.0mol/l
V1=?
C2=.4mol/L
V2=100ml or for this 0.1L
V1 is 20ml
Best way to prepare this is to measure out 20ml of the 2 molar solution and add 80mL to it to get to 100mL
Explanation:
The answer is: lose electrons and form positive ions.
Most metals have strong metallic bond, because of strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.
The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).
For example, magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.
Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.
Answer: The percentage by mass of sulphur in
is 9.36%
Explanation:
Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.
![{\text {Mass percentage}}=\frac{\text {mass of sulphur}}{\text {Total mass}}\times 100\%](https://tex.z-dn.net/?f=%7B%5Ctext%20%7BMass%20percentage%7D%7D%3D%5Cfrac%7B%5Ctext%20%7Bmass%20of%20sulphur%7D%7D%7B%5Ctext%20%7BTotal%20mass%7D%7D%5Ctimes%20100%5C%25)
Given: mass of sulphur = 32 g/mol
mass of
= 342 g/mol
Putting in the values we get:
![{\text {Mass percentage}}=\frac{32g/mol}{342g/mol}\times 100\%=9.36\%](https://tex.z-dn.net/?f=%7B%5Ctext%20%7BMass%20percentage%7D%7D%3D%5Cfrac%7B32g%2Fmol%7D%7B342g%2Fmol%7D%5Ctimes%20100%5C%25%3D9.36%5C%25)
The percentage by mass of sulphur in
is 9.36%
<span>A compound is ''composed'' of elements. The periodic table is made up of elements. Atoms makes up elements and elements when reacted together make compounds.
Na+ and Cl- makes NACL....salt. a compound</span>