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4 years ago

A chemical reactions occurs when, _____?

Chemistry

1 answer:

bixtya [17]4 years ago

7 0

Answer:

Reactants are transformed into products

Explanation:

Chemical reactions are happening everywhere, it may be represented by the following equation:

A(aq) + B(s) ⇒ C(g) + D(l)

The left side represent the reactants that interact to get the products.

In the parenthetycal note is the state of the compound, in this case, aquose solution (aq), solid (s), gas (g), liquid (l)

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How many moles of sodium cyanide (NaCN) would be needed to produce 4.2 moles of sodium sulfate (Na2SO4)? H2SO4 + 2NaCN → 2HCN +

leonid [27]

The purpose of a chemical equation is to relate the amounts of reactants to the amounts of products based on the rate each is consumed. In this problem, one mole of sulfuric acid is consumed along with two moles of sodium cyanide to produce two moles of hydrocyanic acid and one mole of sodium sulfate. The relationship between sodium cyanide and sodium sulfate is 2:1, meaning that two moles of NaCN is required to produce one mole of sodium sulfate.

To produce 4.2 moles of sodium sulfate, two times this amount of NaCN is required. This means that you would need 8.4 moles of sodium cyanide.

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4 0

3 years ago

Read 2 more answers

What is the major organic product obtained from the reaction of ethylbenzene with nitronium ion, followed by benzylic oxidation?

Degger [83]

Answer:

Explanation:

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3 years ago

What is the number of moles in 432g Ba(NO3)2

777dan777 [17]

First there is a need to calculate the molar mass of Ba(NO₃)₂:

137.3 + 2 (14.0) + 6 (16) = 261.3 grams/mole

The molar mass, denoted by M in chemistry refers to a physical characteristic illustrated as the mass of a given component divided by the amount of the component. The molar masses are always denoted in grams/mole.

After finding the molar mass, the number of moles can be identified as:

432 grams / 261.3 g/mol = 1.65 moles of Ba(NO₃)₂.

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4 years ago

What is the molarity of 50gram of calcium carbonate is dissolved in 250ML of water

m_a_m_a [10]

Answer:

Molar Mass of Calcium Carbonate = 100g

given mass = 50g

Number of mole of Calcium Carbonate =50/100 = 0.5 mole

Molarity = mole per litre of volume

Molarity = 0.5 /0.25 = 2mole/litre

Explanation:

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3 years ago

Read 2 more answers

Consider the following system at equilibrium:A(aq)+B(aq) <---> 2C(aq)Classify each of the following actions by whether it

velikii [3]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On addition of reactant at equilibrium shifts the equilibrium in forward direction.
On addition of product at equilibrium shifts the equilibrium in backward direction.
On removal of reactant at equilibrium shifts the equilibrium in backward direction.
On removal of product at equilibrium shifts the equilibrium in forward direction.

$A(aq)+B(aq)\rightleftharpoons 2C(aq)$

Reactants = A , B

Product = C

1. Increase A

On increasing the amount of A at equilibrium will shift the equilibrium in forward or rightward direction.

2. Increase B

On increasing the amount of B at equilibrium will shift the equilibrium in forward or rightward direction.

3. Increase C

On increasing the amount of C at equilibrium will shift the equilibrium in backward or leftward direction.

4. Decease A

On decreasing the amount of A at equilibrium will shift the equilibrium in backward or leftward direction.

5. Decease B

On decreasing the amount of B at equilibrium will shift the equilibrium in backward or leftward direction.

6. Decease C

On decreasing the amount of C at equilibrium will shift the equilibrium in forward or rightward direction.

7. Double A and Halve B

Equilibrium constant of the reaction = K

$K=\frac{[C]^2}{[A][B]}$

On doubling A and halving B, equilibrium constant of the reaction = K'

$K'=\frac{[C]^2}{[2A][\frac{B}{2}]}=\frac{[C]^2}{[A][B]}$

The value of equilibrium constant K' is equal to K, which means that equilibrium will not shift in any direction.

8. Double both B and C

Equilibrium constant of the reaction = K

$K=\frac{[C]^2}{[A][B]}$

On doubling B and C, equilibrium constant of the reaction = K'

$K'=\frac{[2C]^2}{[A][2B]}=\frac{4[C]^2}{[A][2B]}=\frac{2[C]^2}{[A][B]}$

K' = 2 K

The value of equilibrium constant K' is double the K, which means that product is increasing which means that equilibrium will shift in backward or leftward direction.

5 0

3 years ago