1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gala2k [10]
2 years ago
15

Can i titrate a solution of unknown concentration with another solution of unknown concentration and still get a meaningful answ

er
Chemistry
1 answer:
olga2289 [7]2 years ago
6 0

Answer:

No, I don't think so at least

Explanation:

In chemistry, you do calculations to find the concentration of a solution with another solution of KNOWN concentration. Without concentrations of either solution, were would you get values from? Where would you start? :3

You might be interested in
Calcium and bromine have formed a bond. Leading up to this, calcium gave up electrons. It was a(n)
scZoUnD [109]
Leading up to this, calcium gave up 2 valence electrons and thus was denoted as a cation. These 2 electrons were transferred to bromine, which received an overall negative charge because of the addition of 2 valence electrons in its valence shell, and thus formed a negatively charged ion, an anion.

Both formed an ionic bond, due to the electrostatic charge of attraction between the 2 oppositely charged ions. If many ions of Ca and Br are present and numerous ionic bonds have formed it will undergo an arrangement which is that of an ionic lattice, type of structure.
6 0
3 years ago
A ring costs $36 more than a bracelet. the cost of the bracelet is 4/7 the cost of the ring. find the total of the two items.
avanturin [10]
So let's use some equations to represent the data [let R= cost of ring & B= cost of bracelet]

R= B + $ 36 .... (1)

B= \frac{4}{7} × R ... (2)

By using simultaneous equations to solve for B and R.
Substitute eq. (1) into eq. (2)

      B =  \frac{4}{7} × (B + $36)

      B = \frac{4}{7}B + \frac{144}{7}

     ( \frac{7}{7}  -  \frac{4}{7} ) B =  \frac{144}{7}

     \frac{3}{7} B =   \frac{144}{7}

⇒  B = $48

By substituting value of B into ea (1)

If R = B + $36
   
   R = ($48) + $36
     
      = $84

∴  <span> the total of the two items = R + B
                                             = $84 + $48
</span>                                             = $132

7 0
3 years ago
Which equation represents a neutralization reaction?
abruzzese [7]
C. HNO₃(aq) + KOH(aq) → KNO₃(aq) + H₂O
8 0
3 years ago
A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor
AlexFokin [52]

Answer : The partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of C_2HBrClF_3 = 15.0 g

Mass of O_2 = 22.6 g

Molar mass of C_2HBrClF_3 = 197.4 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_2HBrClF_3 and O_2.

\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole

and,

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole

Now we have to calculate the mole fraction of C_2HBrClF_3 and O_2.

\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971

and,

\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903

Now we have to partial pressure of C_2HBrClF_3 and O_2.

According to the Raoult's law,

p^o=X\times p_T

where,

p^o = partial pressure of gas

p_T = total pressure of gas

X = mole fraction of gas

p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T

p_{C_2HBrClF_3}=0.0971\times 862torr=84torr

and,

p_{O_2}=X_{O_2}\times p_T

p_{O_2}=0.903\times 862torr=778torr

Therefore, the partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

6 0
2 years ago
explain observation made when anhydrous calcium chloride and anhydrous copper (ii) sulphate are separately exposed to the atmosp
Burka [1]

Answer:

Anhydrous calcium chloride  dissolves and becomes liquid

Anhydrous copper (ii) sulphate will produce crystal particles

Explanation:

Anhydrous calcium chloride is deliquescent and hence when it is exposed to air, it absorbs water from air. After absorbing water, it dissolves and after some time a pool of clear liquid appears.

Anhydrous copper (ii) sulphate will form crystal structures  and the following reaction will takes place

CuSO4 + 5 H20 --> CuSO4.5H2O

6 0
2 years ago
Other questions:
  • How is the chemical formula of a compound determined?
    10·1 answer
  • If the complete conversion of 1.383g of XI2 results in the formation of 0.564g of XCl2,what is the atomic mass of the element X
    9·1 answer
  • Using the periodic table, choose the more reactive metal.<br> Ag or Te
    15·2 answers
  • A chemist prepares a sample of helium gas at a certain pressure, temperature and volume and then removes all but a fourth of the
    6·1 answer
  • The formula for mustard gas used in chemical warfare is c4h8scl2 (159.09 g/mol). what is the percentage of hydrogen in the compo
    5·1 answer
  • Which of the changes of state shown in the model happen when thermal energy is added
    9·1 answer
  • Kingdom animalia includes a major phylum known as chordata, which includes the sub-phylum vertebrata. This includes lions like t
    15·1 answer
  • Describe what happens as ice changes to water.
    13·1 answer
  • Which of the following would be a clue that a rock is sedimentary?​
    15·2 answers
  • Alan wants to identify an unknown solid compound. Which statement correctly describes a method he could use to identify the comp
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!