Can i titrate a solution of unknown concentration with another solution of unknown concentration and still get a meaningful answ
1 answer:
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So let's use some equations to represent the data [let R= cost of ring & B= cost of bracelet]
R= B + $ 36 .... (1)
B=
× R ... (2)
By using simultaneous equations to solve for B and R.
Substitute eq. (1) into eq. (2)
B = × (B + $36)
B =B + 
⇒ B = $48
By substituting value of B into ea (1)
If R = B + $36
R = ($48) + $36
= $84
∴ <span> the total of the two items = R + B
= $84 + $48
</span> = $132
R= B + $ 36 .... (1)
B=
By using simultaneous equations to solve for B and R.
Substitute eq. (1) into eq. (2)
B =
B =
⇒ B = $48
By substituting value of B into ea (1)
If R = B + $36
R = ($48) + $36
= $84
∴ <span> the total of the two items = R + B
= $84 + $48
</span> = $132
Answer : The partial pressure of and
are, 84 torr and 778 torr respectively.
Explanation : Given,
Mass of = 15.0 g
Mass of = 22.6 g
Molar mass of = 197.4 g/mole
Molar mass of = 32 g/mole
First we have to calculate the moles of and
.
and,
Now we have to calculate the mole fraction of and
.
and,
Now we have to partial pressure of and
.
According to the Raoult's law,
where,
= partial pressure of gas
= total pressure of gas
= mole fraction of gas
and,
Therefore, the partial pressure of and
are, 84 torr and 778 torr respectively.