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bagirrra123 [75]
3 years ago
5

What is the initial temperature (in Celsius) of a 675 ml balloon if the

Chemistry
1 answer:
RoseWind [281]3 years ago
7 0

Answer: 127 (3.s.f)

Explanation:

Boyle's law states that Volume x pressure = constant

Therefore let's first find the constant: 45 x 1900 = 85500

Then lets plug 675 ml and 85500 into the equation above:

675 x C = 85500

C = 127 (3 s.f.)

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The process by which cells chemically break down small food molecules and release chemical energy for the cell’s use is called
Crazy boy [7]

Answer: HEY THERE!

Explanation: HERE IS YOUR ANSWER

Cellular respiration is what happens inside cells when they use oxygen to transfer energy from food to ATP. Cellular respiration is essential to the transfer of matter and energy through living systems

<em>HOPE THIS HELPED AND HAVE A NICE DAY!</em>

5 0
3 years ago
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True or false? Balanced forces cause a change in motion. <br> How do you know this?
Nat2105 [25]

Answer:

false

Explanation:

Balanced forces do not change the motion of an object. The motion of an object will not change if the forces pushing or pulling the object are balanced.

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3 years ago
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A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm
Maurinko [17]

Answer:

The final temperature at 1050 mmHg is 134.57 ^{\circ}C or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55^{\circ}C = 328 K

Initial pressure = P = 845 mmHg

Assuming final  to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg  

The final temperature is obtained by following relation at constant volume

\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}

The final temperature is 407.57 K

7 0
2 years ago
Given the chemical equation: 2 Pb + O2 → 2 PbO, if 51.8 grams of Pb are formed in this reaction, then 8.00 grams of O2 must have
Nutka1998 [239]

Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

Molar mass of O2 = 32 g

Molar mass of PbO = 207 + 32 = 239 g

Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2

7 0
3 years ago
Identify the most common reaction conditions for the dehydration of 2,3-dimethyl-2-pentanol.Select all that apply.A. The presenc
defon

Answer:

D. The presence of a base catalyst.

E. The presence of an acid catalyst. and

F. The presence of heat.

Explanation:

8 0
3 years ago
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