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bagirrra123 [75]
3 years ago
5

What is the initial temperature (in Celsius) of a 675 ml balloon if the

Chemistry
1 answer:
RoseWind [281]3 years ago
7 0

Answer: 127 (3.s.f)

Explanation:

Boyle's law states that Volume x pressure = constant

Therefore let's first find the constant: 45 x 1900 = 85500

Then lets plug 675 ml and 85500 into the equation above:

675 x C = 85500

C = 127 (3 s.f.)

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Define the chemical reaction?​
Goshia [24]

Answer:

HOPE IT HELPED U ....

Explanation:

Chemical reaction is a process that involves rearrangement of the molecular or ionic structure of a substance, as distinct from a change in physical form or a nuclear reaction.

5 0
3 years ago
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Please help me to do this assignment
kirill [66]

Answer:

1. Objective

2. Objective

3. Opinion

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5. Opinion

6. Opinion

7. Opinion (I think.)

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Explanation:

7 0
3 years ago
What is molarity of 47.0 g KCl dissolved in enough water to give 375 mL of solution?
natita [175]

This question provides us –

  • Weight of \bf  KCl is = 47 g
  • Volume, V = 375 mL

__________________________________________

  • Molar Mass of \bf   KCl –

\qquad \twoheadrightarrow\bf  39.0983 \times 35.453

\qquad \twoheadrightarrow\bf 74.5513

<u>Using formula</u> –

\qquad \purple{\twoheadrightarrow\bf Molarity _{(Solution)} =  \dfrac{ W\times 1000}{MV}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{ 47 \times 1000}{74.5513\times 375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{47000}{27956.7375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \cancel{\dfrac{47000}{27956.7375}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = 1.68117M

\qquad \pink{\twoheadrightarrow\bf Molarity _{(Solution)}  = 1.7M}

  • Henceforth, Molarity of the solution is = 1.7M

___________________________________________

6 0
2 years ago
How many atoms are in 10.1 g Ne
LekaFEV [45]

Answer:

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Tables
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

[Given] 10.1 g Ne

[Solve] atoms Ne

<u>Step 2: Identify Conversions</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})
  2. [DA] Divide/Multiply [Cancel out units]:                                                          \displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne

4 0
3 years ago
Each student in a class placed a 2.00 g sample of a mixture of Cu and Al in a beaker and placed the beaker in a fume hood. The s
Aleks [24]

Answer:

Percentage mass of copper in the sample = 32%

Explanation:

Equation of the reaction producing Cu(NO₃) is given below:

Cu(s)+ 4HNO₃(aq) ---> Cu(NO₃)(aq) + 2NO₂(g) + 2H₂O(l)

From the equation of reaction, 1 mole of Cu(NO₃) is produced from 1 mole of copper. Therefore, 0.010 moles of Cu(NO₃) will be produced from 0.010 mole of copper.

Molar mass of copper = 64 g/mol

mass of copper = number of moles * molar mass

mass of copper = 0.01 mol * 64 g/mol = 0.64 g

Percentage by mass of copper in the 2.00 g sample = (0.64/2.00) * 100%

Percentage mass of copper in the sample = 32%

3 0
3 years ago
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