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galben [10]
3 years ago
8

I really need some with help with this anyone who can help with acceleration and velocity pleasee and thank you

Physics
1 answer:
kykrilka [37]3 years ago
3 0

Answer:

velocity equals distance divided by time and the unit you use after you get the answer is m/s

Explanation:

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Can anyone please tell me the properties of image formed in a spherical mirror?
notsponge [240]

Answer:

The two rays, CY and DM are diverging rays and when extended behind the mirror, they appear to intersect each other at point M'. Therefore, the properties of the images formed here are formed behind the mirror, between the pole and principal focus (f), the images are diminished and are virtual and erect.

Explanation:

<h2>Spherical Mirrors</h2>

  • There are two kinds of spherical mirrors, concave and convex.

  • The focal point (F) of a concave mirror is the point at which a parallel beam of light is "focussed" after reflection in the mirror. ...

  • The focal length (f) and radius of curvature (R) are defined in the diagram at the right.

<h3>hope it helps and thanks for following </h3><h2>please give brainliest </h2>
6 0
3 years ago
Read 2 more answers
What are the advantages of having only one si unit for pressure???
Kazeer [188]
The units would be consistent around the world, allowing for easy comprehension of industrial diagrams and requirements as well as easier communication of engineers and scientists with one another.
6 0
3 years ago
In Fig., block 1 of mass m1 slides from rest along a frictionless ramp from height h = 2.50 m and then collides with stationary
Evgesh-ka [11]

Answer:

Explanation:

Given

initial height h=2.5 m

m_2=2m_1

coefficient of static friction \mu =0.5

When collision is elastic respective velocities after collision is

v_1=\frac{u_1(m_1-m_2)+2m_2u_2}{m_1+m_2}

v_2=\frac{u_2(m_2-m_1)+2m_1u_1}{m_1+m_2}

where u_1 and u_2=initial velocities of object

v_1 and v_2 final velocities of object

u_1=\sqrt{2\times 9.8\times 2.5}

u_1=7 m/s

v_2=\frac{0+2m_1\times 7}{m_1+2m_1}

v_2=\frac{14}{3} m/s

using v^2-u^2=2 as

0-(4.67)^2=2\times (-0.5\times 9.8)\times s

s=2.22\ m

(b)Completely Inelastic

In Completely Inelastic objects stick with each other

m_1u_1=(m_1+m_2)v

v=\frac{u_1}{3}=\frac{7}{3} m/s

using v^2-u^2=2 as

0-(2.33)^2=2\times (-0.5\times 9.8)\times s

s=0.55\ m                          

7 0
4 years ago
If the density of a diamond is 3.5 /cm^ 3 what would be the mass of a diamond whose volume is 0.5 cm ^ 3 ?
Elan Coil [88]

Answer:

1.75g

Explanation:

Given parameters:

Density  = 3.5g/cm³

Volume  = 0.5cm³  

Unknown:

Mass of the diamond  = ?

Solution:

Density is the mass per unit volume of a substance

  Density  = \frac{mass}{volume}  

So;

  Mass  = 3.5 x 0.5  = 1.75g

7 0
3 years ago
You drive 6.00 km at 50.0 km/h and then another 6.00kmat 900 km/h Your average speed over
Cerrena [4.2K]

Explanation:

average speed = total distance travelled / total time travelled

time to travel the first 6km: 6 / 50 = 3/25 (h)

time to travel the next 6km: 6 / 90 = 1/15 (h)

[I think there's problem in the question 'cause 900km/h sounds impossible for normal person to travel in normal condition]

The total time: 3/25 + 1/15 = 14/75 (h)

Average speed over the 12 km drive will be:

\frac{12}{ \frac{14}{75} }  =  \frac{450}{7}  = 64.3 \: km{h}^{ - 1}

8 0
3 years ago
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