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maks197457 [2]
3 years ago
7

Got it

Physics
1 answer:
Nimfa-mama [501]3 years ago
7 0
Force=mass•acceleration
F=ma
15 N= 5kg•a
/5 =. /5
3= acceleration?
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a horse stands on a flat surface if the horse has a mass of 186 kg what is the normal force acting on it
astra-53 [7]
The mass of the horse is 186 kg.

The weight of the horse is
(186 kg)*(9.8 m/s^2) = 1822.8 N

According to Newton's 3rd Law, there is an equal and opposite force between the horse and the surface.
Therefore the normal reactive force is 1822.8 N.

Answer: 1822.8 N

8 0
3 years ago
Read 2 more answers
A flask with a tap has a volume of 200cm3 when full of air, tye flask has a mass of 30.98g. the flask is connected to vacuum pum
fgiga [73]
1. 30.98g
2 D = M / V = 30.98/200 = 0.1549
7 0
3 years ago
Help..... disregard my answers...plz help
swat32
What kind of sorcery

6 0
3 years ago
A circular cylinder has a diameter of 3.0 cm and a mass of 25 g. It floats in water with its long axis perpendicular to the wate
Vilka [71]

Answer:

   f = 5.3 Hz

Explanation:

To solve this problem, let's find the equation that describes the process, using Newton's second law

        ∑ F = ma

where the acceleration is

         a = \frac{d^2 y}{dt^2 }

        B- W = m \frac{d^2 y}{dt^2 }

To solve this problem we create a change in the reference system, we place the zero at the equilibrium point

           B = W

In this frame of reference, the variable y'  when it is oscillating is positive and negative, therefore Newton's equation remains

         B’= m \frac{d^2 y'}{dt^2 }

           

the thrust is given by the Archimedes relation

         B = ρ_liquid g V_liquid

     

the volume is

        V = π r² y'

     

we substitute

          - ρ_liquid g π r² y’ = m \frac{d^2 y'}{dt^2 }

          \frac{d^2 y'}{dt^2} + \rho_liquid \ g \ \pi  r^2/m ) y' \ =0

this differential equation has a solution of type

         y = A cos (wt + Ф)

where

         w² = ρ_liquid g π r² /m

angular velocity and frequency are related

         w = 2π f

         

we substitute

          4π² f² = ρ_liquid g π r² / m

          f = \frac{1}{2\pi } \ \sqrt{ \frac{ \rho_{liquid} \  \pi  r^2 \ g}{m } }

calculate

         f = \frac{1}{2 \pi }  \sqrt{ \frac{ 1000 \ \pi  \ 0.03^2 \ 9.8 }{0.025}  }

         f = 5.3 Hz

6 0
3 years ago
The pulley shown in the attached diagram has a diameter of 30 centimeters and a mass of 19 kilograms. The pulley is a solid disk
aleksandrvk [35]

Answer:

Explanation:

a) I = ½mR² = ½(19)(0.15²) = 0.21375 kg•m²

b) τ = Fnet(r) = (25 - 12)(0.15) = 1.95 N•m

c) CCW

d) a = τ/I = 1.95 / 0.21375 = 9.12280701... = 9.1 rad/s²

e) CCW

4 0
2 years ago
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