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3 years ago

Got it

Physics

1 answer:

Nimfa-mama [501]3 years ago

7 0

Force=mass•acceleration
F=ma
15 N= 5kg•a
/5 =. /5
3= acceleration?

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Which kind of light is used to carry information through optical fibers?

ZanzabumX [31]

Red light would be commonly used due to the longer wavelength

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3 years ago

Select the correct answer.

Pachacha [2.7K]

Answer:

Explanation:

It's c the last one u see

8 0

3 years ago

What is the de Broglie wavelength for a proton with energy 50 keV? Due to the limitations of Canvas, please give the wavelength

ad-work [718]

Answer:

1.2826 x 10^-13 m

Explanation:

$\lambda = \frac{h}{\sqrt{2 m K}}$

Here, k be the kinetic energy and m be the mass

K = 50 KeV = 50 x 1.6 x 10^-16 J = 80 x 10^-16 J

m = 1.67 x 10^-27 kg

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6 0

3 years ago

a tire has a tread pattern with a crevice every 4.00 cm. each crevice makes a single vibration as the tire moves. what is the fr

koban [17]

the frequency (in hz) of these vibrations if the car moves at 24.2 m/s is 605 HZ .

Calculation :

frequency = $\frac{number of contacts}{second}$

frequency = $\frac{24.2 m/s}{1}*100cm*\frac{1}{4cm}$

= 605 HZ

Frequency describes the number of waves passing through a particular location in a particular time. So if the wave takes 1/2 second to travel, the frequency is 2 per second. If it takes 1/100th of an hour, the frequency is 100 per hour.

Frequency is the number of occurrences of a repeating event per unit time. ... sometimes called time-frequency for clarity,

Learn more about frequency here : brainly.com/question/254161

#SPJ4

5 0

1 year ago

You wish to produce an emf of 41.0 mV using an inductor whose inductance is 13.0 H. You start with a current of 1.50 mA through

Molodets [167]

Answer:

The current through the inductor at the end of 2.60s is 9.7 mA.

Explanation:

Given;

emf of the inductor, V = 41.0 mV

inductance of the inductor, L = 13 H

initial current in the inductor, I₀ = 1.5 mA

change in time, Δt = 2.6 s

The emf of the inductor is given by;

$V = L\frac{di}{dt} \\\\V = \frac{L(I_1-I_o)}{dt} \\\\L(I_1-I_o) = V*dt\\\\I_1-I_o = \frac{V*dt}{L}\\\\I_1 = \frac{V*dt}{L} + I_o\\\\I_1 = \frac{41*10^{-3}*2.6}{13} +1.5*10^{-3}\\\\I_1 = 8.2*10^{-3} + 1.5*10^{-3}\\\\I_1 = 9.7 *10^{-3} \ A\\\\ I_1 = 9.7 \ mA$

Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.

6 0

3 years ago