Answer:
30.22 hours
Explanation:
Given data:
A= l² = (2 x 
)² = 4 x 
m²
Length 'L' = 5m
current '
' = 2 A
density of free electrons 'n'= 8.5 x 
/m³
Current Density 'J' = / A
J= 2/4 x
J= 5 x 
A/m²
We can determine the time required for an electron to travel the length of the wire by
T= L/ Vd
Where,
L is length and Vd is drift velocity.
Vd can be defined by J/ n|q|
where,
n is the charge-carrier number density
|q| is is the charge carried by each charge carrier
=>1.6 x 
C
T= L/ Vd
Therefore,
T= L . n|q| / J
T= (4 x 8.5 x x |1.6 x |)/5 x
T= 108800 seconds =>1813.33 minutes
Converting minute into hours:
T= 30.22 hours
Thus, time that is required for an electron to travel the length of the wire is 30.22 hours
Newton’s first law of inertia
Less force, same work
Answer:
1.Animal feed is food given to domestic animals in the course of animal husbandry
2.) Roughages B) Concentrates C) Feed supplements and Feed additives
3. Feed grains
4.pliers, vacuum lifters, magnetic lifters, and stock positioners
Explanation:
<u>1.Animal feed is food given to domestic animals in the course of animal husbandry</u>
<u>2.) Roughages B) Concentrates C) Feed supplements and Feed additives</u>
<u>3. Feed grains </u>
<u>4.pliers, vacuum lifters, magnetic lifters, and stock positioners</u>
we know that the sun is supported by nuclear fusion because the sun is a main-sequence star, meaning it has to use nuclear fusion to keep itself going, no nuclear fusion, no sun.
i hope this helps!
