2<span>cos2(θ)−1 = 0
</span><span>2cos2(θ)=1
</span><span>cos2(θ)=1/2
</span><span>2θ=arc cos1/2
</span><span>2θ=60 degrees
</span><span>θ=30 degrees</span>
Answer:5000000000hertz
Explanation:
Wavelength=6cm=6/100 m=0.06m
Frequency=velocity/wavelength
Frequency=(3×10^8)÷0.06
Frequency=5000000000 hertz
Answer:
-1000 N
Explanation:
First calculate the acceleration:
v² = v₀² + 2a(x - x₀)
(0 m/s)² = (100 m/s)² + 2a (0.05 m)
a = -100,000 m/s²
Now calculate the force:
F = ma
F = (0.010 kg) (-100,000 m/s²)
F = -1000 N
Answer:
To the extent that Stellar spectra look like blackbodies, the temperature of a star can also be measured amazingly accurately by recording the brightness in two different filters. To get a stellar temperature: Measure the brightness of a star through two filters and compare the ratio of red to blue light.
Explanation:
<span>21.5 ft/s^2
The formula for distance traveled under constant acceleration is
d = 0.5 AT^2
where
d = distance
A = acceleration
T = time
Solving for A, gives
d = 0.5 AT^2
2d = AT^2
(1) 2d/T^2 = A
The formula for velocity under constant acceleration is
V = AT
Solving for A, gives
V = AT
(2) V/T = A
Now setting equations (1) and (2) above equal to each other and solving for T:
V/T = 2d/T^2
TV = 2d
(3) T = 2d/V
Now substitute equation (3) into (2) above.
V/T = A
V/(2d/V) = A
V * V/2d = A
V^2/2d = A
Plug in values and calculate.
V^2/2d = A
(44 ft/s)^2/(2*45 ft) = A
(1936 ft^2/s^2)/(90 ft) = A
21.51111111 ft/s^2 = A
Rounding to 3 significant figures gives 21.5 ft/s^2</span>